I would like to see that “shaded region”
The value of B1 shows a fall in demand as price rises by a unit. The point prediction is given as y = 306,560.8
<h3>How to solve the question using the intercept</h3>
The regression equation shows that y= 306,619-27.71.x
b1 = -27.71
The interpretation for b1 is that if the price of this good is increased by 1, then the demand for the good would fall by about 27.71.
<h3>The point prediction for demand</h3>
The regression line equation is given as
y= 306,619-27.71.x
when x which is price is = 2.10
Then the value of y would be:
y = 306,619 - 27.71*2.10
y = 306,560.8
c. a 95% C1 for B1 is given as:
1.96 * 27.71.
= 54.31
Read more on regression lines equations here:
brainly.com/question/25987747
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Answer:
Step-by-step explanation:
As C and D are both at y = -9, the line below V₂ is vertical and located at
x = ½(22 + (-2) = 10
The line between V₁ and V₂ will contain the point halfway between B and D.
x = ½(14 + (-2)) = 6
y = ½(7 + (-9)) = -1
(6, -1)
The slope of the line between V₁ and V₂ is the same as between V₁ and our just found midpoint between B and D
m = (5 - (-1)) / (0 - 6) = -1
so the line equation is
y = -x + 5
Which intersects x = 10 at
y = -10 + 5 = -5
V₂ = (10, -5)
The distance between V₂ and B, C, and D is
d = √((14 - 10)² + (7 - (-5))²) = √160
The distance between V₁ and B, A, and D is
d = √((-10 - 0)² + (15 - 5)²) = √200
As √200 > √160, the dump should be located at V₁ or at least √200 away from any two of the points
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Step-by-step explanation:
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