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adelina 88 [10]
3 years ago
5

What is the equation of this graphed line? Enter your answer in slope-intercept form in the box. -6,-3 6,-7

Mathematics
2 answers:
-BARSIC- [3]3 years ago
7 0
The answer is at the bottom hope this helps

elena-s [515]3 years ago
6 0

Answer:

y = \frac{1}{3}x - 1

Step-by-step explanation:

Let the gradient be calculated as follows:

slope = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

         = \frac{-7-(-3)}{6-(-6)}\\ = -\frac{1}{3}

to find the equation passing through the point we calculate as follows:

- 3= \frac{1}{3} (-6) + b\\   -1 = b

Therefore, the equation of the line is:

y = \frac{1}{3}x - 1

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3 years ago
What is the area of the shaded region? Use 3.14 for pi and round to the nearest tenth
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I would like to see that “shaded region”
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Consider the following data concerning the demand (y) and price (x) of a consumer product the least squares line is found to be
Anastasy [175]

The value of B1 shows a fall in demand as price rises by a unit. The point prediction is given as y = 306,560.8

<h3>How to solve the question using the intercept</h3>

The regression equation shows that y= 306,619-27.71.x

b1 = -27.71

The interpretation for b1 is that if the price of this good is increased by 1, then the demand for the good would fall by about 27.71.

<h3>The point prediction for demand</h3>

The regression line equation is given as

y= 306,619-27.71.x

when x which is price is = 2.10

Then the value of y would be:

y = 306,619 - 27.71*2.10

y = 306,560.8

c. a 95% C1 for B1 is given as:

1.96 * 27.71.

= 54.31

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7 0
2 years ago
I need the answers for this question. I am confused
noname [10]

Answer:

Step-by-step explanation:

As C and D are both at y = -9, the line below V₂ is vertical and located at

x = ½(22 + (-2) = 10

The line between V₁ and V₂ will contain the point halfway between B and D.

x = ½(14 + (-2)) = 6

y = ½(7 + (-9)) = -1

(6, -1)

The slope of the line between V₁ and V₂ is the same as between V₁ and our just found midpoint between B and D

m = (5 - (-1)) / (0 - 6) = -1

so the line equation is

y = -x + 5

Which intersects x = 10 at

y = -10 + 5 = -5

V₂ = (10, -5)

The distance between V₂ and B, C, and D is

d = √((14 - 10)² + (7 - (-5))²) = √160

The distance between V₁ and B, A, and D is

d = √((-10 - 0)² + (15 - 5)²) = √200

As √200 > √160, the dump should be located at V₁ or at least √200 away from any two of the points

5 0
3 years ago
Solve for m : -5m + 14 = 9
Eddi Din [679]

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Step-by-step explanation:

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