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3 years ago

Let f(x)=x^2+x−42 . Enter the x-intercepts of the quadratic function

Mathematics

1 answer:

Lesechka [4]3 years ago

6 0

Answer:

x = - 7, x = 6

Step-by-step explanation:

to find the x- intercepts set f(x) = 0, that is

x² + x - 42 = 0

To factor, consider the factors of - 42 which sum to + 1

These are + 7 and - 6

(x + 7)(x - 6) = 0

equate each factor to zero and solve for x

x + 7 = 0 ⇒ x = - 7

x - 6 = 0 ⇒ x = 6

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Let ​ f(x)=x^2+x−42 ​. Enter the x-intercepts of the quadratic function

Let f(x)=x^2+x−42 . Enter the x-intercepts of the quadratic function