Question

1. A researcher is testing the claim that adults consume an average of at least 1.85 cups of coffee per day. A sample of 35 adults shows a sample mean of 1.70 cups per day with a sample standard deviation of 0.4 cups per day. Test the claim at a 5% level of significance. What is your conclusion?

Answer 1

Answer:

reject H0

Step-by-step explanation:

Given that a researcher is testing the claim that adults consume an average of at least 1.85 cups of coffee per day.

A sample of 35 adults shows a sample mean of 1.70 cups per day with a sample standard deviation of 0.4 cups per day.

$H_0:\bar x =1.85\\H_a: \bar x \geq 1.85$

(right tailed test at 5% level of significance)

$\bar x = 1.70\\s = 0.4\\Se = \frac{0.4}{\sqrt{35} } \\=0.0676$

Test statistic t = mean difference/std error =$\frac{1.70-1.85}{0.0676} \\=-2.22$

df = 34

t critical = -1.697

Since our test statistic < t critical we reject null hypothesis..