Answer:
The probability of 1 or less children from that group to learn how to swim before 6 years of age is 0.072
Step-by-step explanation:
In this case we need to compute the probability of none of these 12 children learns to swim before 6 years of age. This is given by:
p(0) = (1 - 0.312)^(12) = 0.688^(12) = 0.01124
We now need to calculate the probability that one child learns to swim before 6 years of age.
p(1) = 12*0.312*(1 - 0.312)^(11) = 3.744*(0.688)^(11)
p(1) = 3.744*0.01634
p(1) = 0.0612
The probability of 1 or less children from that group to learn how to swim before 6 years of age is:
p = p(0) + p(1) = 0.01124 + 0.0612 = 0.07244
Answer:
I believe it is 18 + the square root of 26.
Step-by-step explanation:
The slope of line BC should be 5/1 because it goes up 5 times and to the right once. If you square root 26 you get 5.09.
Answer:
Step-by-step explanation:
![\huge \sqrt[3]{9 {x}^{4} } . \sqrt[3]{3 {x}^{8} } \\ \\ \huge = \sqrt[3]{9 {x}^{4} \times 3 {x}^{8} } \\ \\\huge = \sqrt[3]{27 {x}^{12} } \\ \\ \huge\orange{= 3 {x}^{4} }](https://tex.z-dn.net/?f=%5Chuge%20%5Csqrt%5B3%5D%7B9%20%7Bx%7D%5E%7B4%7D%20%7D%20.%20%20%5Csqrt%5B3%5D%7B3%20%7Bx%7D%5E%7B8%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%5Chuge%20%3D%20%20%5Csqrt%5B3%5D%7B9%20%7Bx%7D%5E%7B4%7D%20%5Ctimes%203%20%7Bx%7D%5E%7B8%7D%20%20%7D%20%20%5C%5C%20%20%5C%5C%5Chuge%20%20%3D%20%20%5Csqrt%5B3%5D%7B27%20%7Bx%7D%5E%7B12%7D%20%20%7D%20%20%5C%5C%20%20%5C%5C%20%20%5Chuge%5Corange%7B%3D%203%20%7Bx%7D%5E%7B4%7D%20%7D)
