3x - 4 + x^2 - 1 + 2x^2 - 15
3x^2 + 3x - 20
I wasn't sure if you wanted me to solve for x, but I did anyways.
x ≈ 1.86, or -2.86
Answer:
*gives help*
:)
Step-by-step explanation:
Answer:
95 city and 175 highway miles.
Step-by-step explanation:
The driver gets 20 mpg in city, and 28 mpg on the highway.
An equation that could be written is
20x+28y=270
This equation accounts for the distance traveled.
x+y=11
This equotion accounts for how many gallons were driven.
Multiply the bottom equation by 20, so you can solve the set of equations.
20x+28y=270
20x+20y=220
subtract them
8y=50
y=6.25
now plug this back into x+y=11
x+6.25=11
x=4.75
Now 4.75×20=95 city miles and 6.25×28=175 highway miles.
Answer:
(3x+4)(5x+7)
Step-by-step explanation:
15x^2
+41x+28
Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2
+ax+bx+28. To find a and b, set up a system to be solved.
a+b=41
ab=15×28=420
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.
1,420
2,210
3,140
4,105
5,84
6,70
7,60
10,42
12,35
14,30
15,28
20,21
Calculate the sum for each pair.
1+420=421
2+210=212
3+140=143
4+105=109
5+84=89
6+70=76
7+60=67
10+42=52
12+35=47
14+30=44
15+28=43
20+21=41
The solution is the pair that gives sum 41.
a=20
b=21
Rewrite 15x^2
+41x+28 as (15x^2
+20x)+(21x+28).
(15x^2
+20x)+(21x+28)
Factor out 5x in the first and 7 in the second group.
5x(3x+4)+7(3x+4)
Factor out common term 3x+4 by using distributive property.
(3x+4)(5x+7)
Answer:
30 (.1)=3
or you could do
30×.1=3
you could use either one but I dont know what the person your turning the work in requires the equation to look like
