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satela [25.4K]
3 years ago
14

PLEASE HELP!!!!!!

Mathematics
1 answer:
Murrr4er [49]3 years ago
6 0
I hope this helps you

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I Need to find the Function Operations​
Alinara [238K]

Answer:

1) (f+g)(x)=2x^2+3x-6

2) (f-g)(x)=2x^2+x

3) (f \cdot g)(x)=2x^3-4x^2-9x+9

Step-by-step explanation:

So we have the two functions:

f(x)=2x^2+2x-3\text{ and } g(x)=x-3

And we want to find (f+g)(x), (f-g)(x), and (f*g)(x).

1)

(f+g)(x) is the same to f(x)+g(x). Substitute:

(f+g)(x)=f(x)+g(x)\\=(2x^2+2x-3)+(x-3)

Combine like terms:

=(2x^2)+(2x+x)+(-3-3)

Add:

=2x^2+3x-6

So:

(f+g)(x)=2x^2+3x-6

2)

(f-g)(x) is the same to f(x)-g(x). So:

(f-g)(x)=f(x)-g(x)\\=(2x^2+2x-3)-(x-3)

Distribute:

=(2x^2+2x-3)+(-x+3)

Combine like terms:

=(2x^2)+(2x-x)+(-3+3)

Simplify:

=2x^2+x

So:

(f-g)(x)=2x^2+x

3)

(f*g)(x) is the same to f(x)*g(x). Thus:

(f\cdot g)(x)=f(x)\cdot g(x)\\=(2x^2+2x-3)(x-3)

Distribute:

=(2x^2+2x-3)(x)+(2x^2+2x-3)(-3)

Distribute:

=(2x^3+2x^2-3x)+(-6x^2-6x+9)

Combine like terms:

=(2x^3)+(2x^2-6x^2)+(-3x-6x)+(9)

Simplify:

=2x^3-4x^2-9x+9

So:

(f \cdot g)(x)=2x^3-4x^2-9x+9

4 0
3 years ago
3x^2=12 solve the equation algebraically?
yawa3891 [41]

Answer: 2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Help with the one that’s blank please
zepelin [54]

Hibuscsjsbbzjd should d d d d g a g s g d s f d

6 0
3 years ago
if h=-16t ²+160t represents the height of a rocket in T seconds after it was fired when will the rocket hit the ground?
makkiz [27]

Answer:

The time after which the rocket hit the ground is 5 seconds

Step-by-step explanation:

Given as :

The distance of the cover by rocket at the height h = - 16 t² + 160 t

Let the time after which rocket hit the ground = T seconds

Now, When the rocket hits the ground, then at that time, the velocity of the rocket becomes zero.

I.e velocity = \frac{\partial h}{\partial t} = 0

Or, v = \frac{\partial h}{\partial t} = 0

Now, v = \frac{\partial h}{\partial t}

Or, v = \frac{\partial (-16t^{2}+160t)}{\partial t}

or, v = - 32 t + 160

Now, ∵ velocity of rocket after reaching the ground becomes zero

So, v = - 32 t + 160 = 0

Or, 32 t = 160

Or, t = \frac{160}{32}

∴ t = 5 sec

So, The time after which the rocket hit the ground = 5 sec

Hence The time after which the rocket hit the ground is 5 seconds answer

6 0
3 years ago
Chloe needed to get her computer fixed. She took it to the repair store. The technician at the store worked on the computer for
yawa3891 [41]
389.50 minus 197 for parts will give you your answer
5 0
3 years ago
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