Answer:
m∠A = 50°
m∠B = 70°
m∠C = 60°
Step-by-step explanation:
Determine the measure of angle A, B, and C in triangle ABC. If m∠A=(x-10)°,m∠B=(2x-50)°,and m∠C=x°
In a Triangle, the sum of the interior angles of a triangle = 180°
Step 1
We solve for x
Hence:
m∠A + m∠B + m∠C= 180°
(x-10)°+ (2x-50)°+ x° = 180°
x - 10 + 2x - 50 + x = 180°
4x - 60 = 180°
4x = 180° + 60°
4x = 240°
x = 240°/4
x = 60°
Step 2
Solving for each measure
x = 60°
m∠A=(x-10)°
= 60° - 10°
= 50°
m∠B=(2x-50)°
= 2(60)° - 50°
= 120° - 50°
= 70°
m∠C=x°
= 60°
Given:
The expression is
![\sqrt[3]{48}=\sqrt[3]{8\cdot \_\_}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D%3D%5Csqrt%5B3%5D%7B8%5Ccdot%20%5C_%5C_%7D%3D)
To find:
The simplified form of the expression.
Solution:
We have,
![\sqrt[3]{48}=\sqrt[3]{8\cdot \_\_}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D%3D%5Csqrt%5B3%5D%7B8%5Ccdot%20%5C_%5C_%7D%3D)
The expression
can be written as
![\sqrt[3]{48}=\sqrt[3]{8\cdot 6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D%3D%5Csqrt%5B3%5D%7B8%5Ccdot%206%7D)
![[\because \sqrt[3]{ab}=\sqrt[3]{a}\sqrt[3]{b}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%5B3%5D%7Bab%7D%3D%5Csqrt%5B3%5D%7Ba%7D%5Csqrt%5B3%5D%7Bb%7D%5D)
![\sqrt[3]{48}=2\cdot \sqrt[3]{6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D%3D2%5Ccdot%20%5Csqrt%5B3%5D%7B6%7D)
![\sqrt[3]{48}=2\sqrt[3]{6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D%3D2%5Csqrt%5B3%5D%7B6%7D)
Therefore,
.
we have

we know that

and

substitute in the expression



therefore
<u>the answer is</u>

It would be 60. He sold his painting for 50 which was 10 less that the original price. So 50+10=60