2 years ago

What is the equation in point slope form of the line that passes the points (2,-3) and(-5,8)

1 answer:

Grace [21]2 years ago

4 0

Answer:

y+3=-11/7(x-2)

Step-by-step explanation:

y-y1=m(x-x1)

m=(y2-y1)/(x2-x1)

m=(8-(-3))/(-5-2)

m=(8+3)/(-7)

m=11/-7

m=-11/7

y-(-3)=-11/7(x-2)

y+3=-11/7(x-2)

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