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2 years ago

What is the equation in point slope form of the line that passes the points (2,-3) and(-5,8)

Mathematics

1 answer:

Grace [21]2 years ago

4 0

Answer:

y+3=-11/7(x-2)

Step-by-step explanation:

y-y1=m(x-x1)

m=(y2-y1)/(x2-x1)

m=(8-(-3))/(-5-2)

m=(8+3)/(-7)

m=11/-7

m=-11/7

y-(-3)=-11/7(x-2)

y+3=-11/7(x-2)

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3 years ago

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Rudik [331]

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3 years ago

Read 2 more answers

(-4, -7) and (-6, 9) in slope-intercept form. Show work

BigorU [14]

Answer:

Equation of line in slope-intercept form is: y = -8x-39

Step-by-step explanation:

Given points are:

(-4, -7) and (-6, 9)

The slope-intercept form is given by the equation

$y = mx+b$

Here m is the slope of the line and b is the y-intercept.

m is found using the formula

$m = \frac{y_2-y_1}{x_2-x_1}$

Here

(x1,y1) = (-4-7)

(x2,y2) = (-6,9)

Putting the values in the formula

$m = \frac{9+7}{-6+4} = \frac{16}{-2} = -8$

Putting slope in general equation

$y = -8x+b$

Putting (-6,9) in the equation

$9 = -8(-6)+b\\9 = 48+b\\b = 9-48\\b = -39$

Putting the value of b we get

$y = -8x-39$

Hence,

Equation of line in slope-intercept form is: y = -8x-39

5 0

3 years ago

Substitute 10 for z in z -5 < 7

EleoNora [17]

Then it would be 10-5 < 7
so if you solved it it would be 5 < 7
So this statement is true

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2 years ago