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ki77a [65]
2 years ago
13

Megan’s TV had a base price of $189 and the sales tax was 6.88%. Over the next four years, the TV consumed an average of $0.06 o

f electricity every day. It also needed repairs twice, costing $29 each time. After four years, Megan got a new TV. What was the lifetime cost of Megan’s TV? (Remember that one in every four years is a leap year.)
a.
$357.68
b.
$318.66
c.
$347.66
d.
$351.65
Mathematics
2 answers:
Leni [432]2 years ago
8 0

Answer:

Step-by-step explanation:

price of tv and sales tax = 1.0688×$189 = $202.0032 ≅ $202.00

4 years = 3×365 days + 366 days = 1461 days

cost of electricity = 1461 days × $0.06/day = $87.66

lifetime cost = purchase price + electricity + repairs

= $202.00 + $87.66 + 2·$29

= $347.66

Maksim231197 [3]2 years ago
3 0

Answer:

347.66 is your answer

Step-by-step explanation:

glad to help btw the answer is on edge 2021.

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aleksandrvk [35]

Answer:

a. 11/5 pi; -9/5 pi

Step-by-step explanation:

Coterminal angles are those which have a common terminal side. For example 30° is coterminal with −330° and 390° (see figure).

From the example we can see that the following expressions must be fulfilled:

positive angle - reference angle = 360°

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where positive angle is 390°, reference angle is 30° and negative angle is -330°. In this problem reference angle is pi/5. Also, we have to change 360° for its equivalent in radians, i. e., 2 pi. So,

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5 0
3 years ago
Assume that females have pulse rates that are normally distributed with a mean of μ=73.0 beats per minute and a standard deviati
Gennadij [26K]

Answer:

a. the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly​ selected,  the probability that they have pulse rates with a mean less than 76 beats per minute is 0.8849

c.   D. Since the original population has a normal​ distribution, the distribution of sample means is a normal distribution for any sample size.

Step-by-step explanation:

Given that:

Mean μ =73.0

Standard deviation σ =12.5

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Then : X \sim N ( μ = 73.0 , σ = 12.5)

The probability that her pulse rate is less than 76 beats per minute can be computed as:

P(X < 76) = P(\dfrac{X-\mu}{\sigma}< \dfrac{X-\mu}{\sigma})

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now; we have a sample size n = 25

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In order to determine the probability in part (b);  the  normal distribution is perfect to be used here even when the sample size does not exceed 30.

Therefore option D is correct.

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Answer:

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