The consecutive positive integers would be: x and (x+1), We would have to solve the following equation to find these numbers: x(x+1)-[x+(x+1)]=29 x²+x-2x-1=29 x²-x-30=0 x=[1⁺₋√(1+120)]/2 x=(1⁺₋11)/2 We have two possible solutions: x₁=(1-11)/2=-5 then: (x+1)=-5+1=-4 This is not the solution. x₂=(1+11)/2=6 then: (x+1)=6+1=7 This solution is right.
