Atoms of elements below atomic number 20 do not split because of stable nucleus.
Stability of nucleus is determined by neutron/proton ratio.
For light stable nuclides, number of protons ans neutrons are same. For heavy nuclides, number of neutrons is more than the number of protons.
Here the type of decay is alpha decay because number of nucleons(protons and neutrons) changes.
Hence option d is correct.
Answer:
Alpha decay forms new element with two fewer protons and two fewer neutrons; Beta decay forms new element with one more proton and one fewer neutron.
Explanation:
Answer: 8 dots would be needed to represent the outer electrons for an atom of neon in an electron dot diagram.
Explanation:
Electron-dot diagram is also known as Lewis-dot structure. It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule. The valence electrons are represented by 'dot'.
As atomic number of neon is 10 and we know that neon has 10 electrons with electronic configuration of 2,8 and thus has '8' valence electrons.
Therefore, the total number of valence electrons is 8 and 8 dots would be needed to represent the outer electrons for an atom of neon in an electron dot diagram.
