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andreev551 [17]
3 years ago
6

Suppose in an experiment to determine the amount of sodium hypochlorite in bleach, 0.0000524 mol K I O 3 were titrated with an u

nknown solution of N a 2 S 2 O 3 and the endpoint was reached after 17.80 mL . How many moles of N a 2 S 2 O 3 did this require
Chemistry
1 answer:
11111nata11111 [884]3 years ago
4 0

<u>Answer:</u> The amount of sodium thiosulfate required is 2.62\times 10^{-5} moles

<u>Explanation:</u>

Moles of KIO_3 solution given = 0.0000524 moles

The chemical equation for the reaction of potassium iodate and sodium thiosulfate follows:

2KIO_3+Na_2S_2O_3\rightarrow K_2S_2O_3+2NaIO_3

By Stoichiometry of the reaction:

2 moles of potassium iodate reacts with 1 mole of sodium thiosulfate

So, 0.0000524 moles of potassium iodate will react with = \frac{1}{2}\times 0.0000524=0.0000262mol of sodium thiosulfate

Hence, the amount of sodium thiosulfate required is 2.62\times 10^{-5} moles

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AgC2H3O2 + K2CrO4 = Ag2CrO4 + KC2H3O2 How many moles of silver chromate, Ag2CrO4 are produced in this reaction
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<h3>Reaction stoichiometry</h3>

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2 AgC₂H₃O₂ + K₂CrO₄  → Ag₂CrO₄ + 2 KC₂H₃O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

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<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

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