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andreev551 [17]
3 years ago
6

Suppose in an experiment to determine the amount of sodium hypochlorite in bleach, 0.0000524 mol K I O 3 were titrated with an u

nknown solution of N a 2 S 2 O 3 and the endpoint was reached after 17.80 mL . How many moles of N a 2 S 2 O 3 did this require
Chemistry
1 answer:
11111nata11111 [884]3 years ago
4 0

<u>Answer:</u> The amount of sodium thiosulfate required is 2.62\times 10^{-5} moles

<u>Explanation:</u>

Moles of KIO_3 solution given = 0.0000524 moles

The chemical equation for the reaction of potassium iodate and sodium thiosulfate follows:

2KIO_3+Na_2S_2O_3\rightarrow K_2S_2O_3+2NaIO_3

By Stoichiometry of the reaction:

2 moles of potassium iodate reacts with 1 mole of sodium thiosulfate

So, 0.0000524 moles of potassium iodate will react with = \frac{1}{2}\times 0.0000524=0.0000262mol of sodium thiosulfate

Hence, the amount of sodium thiosulfate required is 2.62\times 10^{-5} moles

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3 years ago
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4 years ago
Read 2 more answers
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