3 years ago

Please Help simple problem for 30 pointsTelling me / showing work will get you brainy

Mathematics

1 answer:

Norma-Jean [14]3 years ago

8 0

Answer:

Step-by-step explanation:

Start with the circumference.

C = 2*pi*r

C = 301.5

pi = 3.14

r = ??

Solution

301.5=3.14 * 2 * r

301.5 = 6.28*r

r = 301.5/6.28

r = 48.01

So the radius = 48.01

The diameter is twice as much or 48.01 * 2 = 96.02

You might be interested in

Determine the sum of the areas of the three triangles shown above.

N76 [4]

I will be there at the same time I don't hear

6 0

3 years ago

Which equation represents the circle described? (in picture)

Sedaia [141]

You are right. In circle equation we have =r² so the correct answer will be C od D. But we have to calculate the center of a circle.

$x^2+y^2-8x-6y+24=0\quad|-24\\\\(x^2-8x)+(y^2-6y)=-24$

Complete the square:

$x^2-8x+a^2\implies a=\dfrac{8x}{2x}=4\implies x^2-8x+4^2\\\\\\y^2-6y+b^2\implies b=\dfrac{6y}{2y}=3\implies y^2-6y+3^2$

And we have:

$(x^2-8x)+(y^2-6y)=-24\\\\(x^2-8x+4^2)-4^2+(y^2-6y+3^2)-3^2=-24\\\\
(x-4)^2+(y-3)^2-16-9=-24\\\\(x-4)^2+(y-3)^2-25=-24\quad|+25\\\\\boxed{(x-4)^2+(y-3)^2=1}$

So the answer is C (the same left side of equation).

6 0

3 years ago

The work W required to move a particle from a far distance to within radius r of another particle varies jointly as the product

tangare [24]

Answer:

W = kq1q2 / r

Step-by-step explanation:

W varies jointly as the product of q1 and q2 and inversely as radius r

Product of q1 and q2 = q1q2

W = (k*q1"q2) / r

W = kq1q2 / r

Where,

W = work

q1 = particle 1

q2 = particle 2

r = radius

k = constant of proportionality

The answer is W = kq1q2 / r

5 0

3 years ago

Find the area<br><br> length=x+10 width=2x+5 <br><br> explain/show your steps

LenKa [72]

2x^2 + 25x + 50 not sure about the steps

3 0

2 years ago

The ordered pairs (1,3),(3,5),(5,7) Represent a function what is a rule that represents this function

mash [69]

Answer:

(3,5),(3,1),(5,7)

Step-by-step explanation:

4 0

2 years ago