How much bigger is the Sum of first 50 even numbers than the sum of first 50 odd numbers?
1 answer:
Answer:
50
Step-by-step explanation:
Sum Even numbers
n = 50
d = 2
a1 = 2
The last number is
an = a1 + (n-1)d
an = 2 + (50 - 1)*2
an = 2 + 49 * 2
an = 2 + 98
an = 100
Sum of the even numbers
Sum = (a1 + a50)*n/ 2
Sum = (2 + 100)*50/2
sum = 102 * 25
sum = 2550
Sum of the first 50 odd numbers
a1 = 1
n = 50
d = 2
l = ?
Find l
l = a1 + (n - 1)*2
l = 1 + 49*2
l = 99
Sum
Sum = (1 + 99)*50/2
Sum = 2500
The difference and answer is 2550 - 2500 = 50
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Answer:
30%
Step-by-step explanation:
the first solution -30% will be 45% and the second solution added by 30% will be 45%
Number of vertices of hexagon is 6
7+8 is the answer
But it can also be 11
Answer:77 and 87
Step-by-step explanation:
7×6=42 + 5+7=35/\ 35+42=77(first outcome)
7×6=42 + 5×9=45/\42+45=87 (second outcome.
A. Negative ♡
Im pretty sure about this
