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3 years ago

What is the answer to f/3 < -2

Mathematics

1 answer:

Hitman42 [59]3 years ago

4 0

Answer:

1 i think

Step-by-step explanation:

hope this helps :) have a nice day :) :)

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Y = x2 – 3x + 10, find f(–2)

Ann [662]

Answer:Hello

I think it's 12

Step-by-step explanation:

Actually at first you should plus this tow parameters:2x-3x+10

and then you can put(-2)instead (x).

Now you find answer.

6 0

3 years ago

Where does the graph of y= sin x from x = 0 to x = 217 start?

choli [55]

Answer:

B) at an x-intercept

Step-by-step explanation:

Hope this helps :))

5 0

2 years ago

Rachel Newton scored 33 points in a recent basketball game. She scored 21 times, making several free throws worth 1 point each a

SpyIntel [72]

Step-by-step explanation:

Step 1:

Let Rachel scored 33 points in total

Let a be the 1 point and b be the 2 point.

a = 21 points scored by 1 point. We want to find b

Step 2:

a+b=33

b= 33-a

= 33-21

= 12

b=12 points which means 6 double points

3 0

3 years ago

What is the slope of the line?

dsp73

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Slope = rise/ run

Slope = 4/2

Slope = 2

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

7 0

3 years ago

Use these functions to answer the questions.

Elenna [48]

Part A
We have $f\left(x\right)=\left(x+3\right)^2-1$ . To solve for the x-intercept, we set f(x) equal to 0. That is
$\left(x+3\right)^2-1=0$

$\left(x+3\right)^2=1$

Take the square root of both sides,
$x+3=1$

$x=-2$

The x-intercept is (-2,0).

To solve for the y-intercept, we set x=0. That is
$y=\left(0+3\right)^2-1=3^2-1=9-1=8$

The y-intercept is (0, 8)

The coordinates of the optimum point are actually the vertex which can be easily seen from the vertex form equation given above. The minimum point is (-3, -1).

Part B.
We have $g\left(x\right)=-2x^2+8x+3$ .
Factor out -2
$=-2\left(x^2-4x\right)+3$

Complete the square
$=-2\left(x^2-4x+4\right)+3-2\left(4\right)$

Simplify
$g(x)=-2\left(x-2\right)^2-5$

Part C
We have $h\left(t\right)=-16t^2+28t$ .
The maximum height is 12.25 feet after 0.875 seconds from the time of the jump. The dolphin will be back in the water after 1.75 seconds. The graph of the jump is shown in the photo.

4 0

3 years ago