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shtirl [24]
3 years ago
10

Part A: Is there any correlation between the number of workers in a factory and the number of units produced daily? Justify your

answer. (4 points) Part B: Write a function that best fits the data. (3 points) Part C: What does the slope and y-intercept of the plot indicate? (3 points)

Mathematics
1 answer:
aev [14]3 years ago
7 0

Step-by-step explanation:

PART A

it wpuld be a correlation

PART B Write a function which best fits the data.

So, f(x)=5x+2

PART C

slope and y-intercept of the plot indicates that its going up 5 positive points

The change in Y over the change in X.

The number of units of outputs per number of workers.

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Y 20 18 16 14 12 Total Cost ($) 10 000 2 3 1 2 Time (hours) 2. 3 4 6 8 y = IX +​
Monica [59]
To find the m(slope) of our graph we can take two points from the graph, im going to use (0,2) and (1,8) the formula for slope is y2-y1/x2-x1
Plug the points in to get 8-2/1-0
The slope of this equation is 6.

For the y-intercept we just find where the line meets the y-axis and that is at 2.

The equation for this graph is y=6x+2
8 0
3 years ago
In a group of 15 children the ratio of the boy : the girl is 2: 3: 5 more girls join the group. Calculate the percentage of boys
marta [7]

Answer:

Percentage of new group boys = 30%

Percentage decrease for the boys = 10%

Increase percent of the girls = 10%

Step-by-step explanation:

Given:

Number of children = 15

Ratio (Boys to Girls) = 2 : 3

Number of more girls join = 5

Find:

Percentage of boys in new group

Percentage decrease for the boys

Increase percent of the girls

Computation:

Number of boys = 15[2/5]

Number of boys = 6

Number of girls = 15[3/5]

Number of girls = 9

Percentage of boys = [6 / 15]100

Percentage of boys = 40%

Percentage of girls = [9 / 15]100

Percentage of girls = 60%

New number of students = 15 + 5

New number of students = 20

New number of boys = 6

New number of girls = 9 + 5 = 14

Percentage of new group boys = [6 / 20]100

Percentage of new group boys = 30%

Percentage of new group girls = [14 / 20]100

Percentage of new group girls = 70%

Percentage decrease for the boys = 40% - 30%

Percentage decrease for the boys = 10%

Increase percent of the girls = 70% - 60%

Increase percent of the girls = 10%

8 0
3 years ago
5.4x 7 \4 simplify this wat do i do ?????
Artyom0805 [142]

Hey there!☺

Answer:\boxed{9.45}

Explanation:

5.4\times\frac{7}{4}

Multiply 5.4 by 7:

5.4\times7=37.8

Now divide 37.8 by 4:

37.8/4=9.45

9.45\text{ is your answer.}

Hope this helps!☺

7 0
3 years ago
EXPLAIN YOUR ANSWER NEED HELP ASAP
Dennis_Churaev [7]
The radius is half the diameter. 19*2=38. The diameter is 38.
7 0
3 years ago
if you roll a fair 6-sided die 9 times, what is the probability that at least 2 of the rolls come up as a 3 or a 4?
Kay [80]

Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • There are 9 rolls, hence n = 9.
  • Of the six sides, 2 are 3 or 4, hence p = \frac{2}{6} = 0.3333

The desired probability is:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{9,0}.(0.3333)^{0}.(0.6667)^{9} = 0.026

P(X = 1) = C_{9,1}.(0.3333)^{1}.(0.6667)^{8} = 0.117

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.026 + 0.117 = 0.143

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.143 = 0.857

0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For more on the binomial distribution, you can check brainly.com/question/24863377

7 0
3 years ago
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