So what you do is go 5(3y+5)-4y=14 which equals 15y+25-4y=14 which turns into 11y+25=14 than you move the 25 over which equals 11y=-11 so y=-1 then you enter -1 in for y which looks like 5x-4(-1)=14 than you solve that which is 5x+4=14 than you move the 4 over and you get 5x=10 than x=2
x=2
y=-1
Step-by-step explanation:
1. vertical angles. x = 5
2. supplementary x = 12
3. complementary x = 7
4 Supplementary x = 17
5. sQR = 118
RQT = 62
6 LNK = 47, JNM = 47
Answer:
Imma just go A
Step-by-step explanation:
Answer:
Yes, an arrow can be drawn from 10.3 so the relation is a function.
Step-by-step explanation:
Assuming the diagram on the left is the domain(the inputs) and the diagram on the right is the range(the outputs), yes, an arrow can be drawn from 10.3 and the relation will be a function.
The only time something isn't a function is if two different outputs had the same input. However, it's okay for two different inputs to have the same output.
In this problem, 10.3 is an input. If you drew an arrow from 10.3 to one of the values on the right, 10.3 would end up sharing an output with another input. This is allowed, and the relation would be classified as a function.
However, if you drew multiple arrows from 10.3 to different values on the right, then the relation would no longer be a function because 10.3, a single input, would have multiple outputs.
