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Finger [1]
4 years ago
12

Calculate the sum of the series whose partial sums are given.

Mathematics
1 answer:
aleksley [76]4 years ago
7 0
When we calculate the sum of the series C∞, n=1 ∑ an
whose partial sums are given
sn = 2 − 9(0.9)ⁿ
We can get an answer which is 2.
It has an infinite number of terms, the infinite series. The partial sum is the sum of the first n terms, Sn. The answer in this question is 2.
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Solve the following equation for x.​
sveticcg [70]

Answer:

If you just solve normally, you will get x=2 and x=-3. But if you plug these in to check your work, you will find that they are wrong. Your answer is no solution

Step-by-step explanation:

ln(2x+3)+ln(x-2)=ln(x^2-2x)

<em>Rule: log(a) + log(b) = log(a*b)</em>

ln( (2x+3)(x-2) ) = ln(x^2-2x)

<em>Rule: If log(a) = log(b) then a = b</em>

(2x+3)(x-2) = x^2 - 2x

2x^2-x-6=x^2-2x

x^2+x-6=0

<em>Using Quadratic Formula:</em>

x = 2 and x = -3

But, plugging these numbers back into the original equation is false!

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3 years ago
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Sonja [21]

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1.024

Step-by-step explanation:

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3 years ago
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6 0
3 years ago
Is each line parallel, perpendicular or neither parallel nor perpendicular to the linex+2y=6?
klio [65]

The correct answers are :

y=-1/2x+5 is parallel.

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x+2y=2 is parallel.

<h3>What are parallel lines and perpendicular lines ?</h3>

It is argued that two non-vertical lines in the same plane that have the same slope are parallel.

In terms of geometry, parallel lines are two separate lines that never cross each other and are located in the same plane. They may be vertical or horizontal. Examples of parallel lines can be found all around us on railroad tracks, in lines of notebooks, and at zebra crossings in daily life. It is impossible for two parallel lines to cross. Perpendicular lines are those that cross at a right angle when two non-vertical lines in the same plane.

Perpendicular lines are two different lines that cross at a right angle of 90 degrees.

To know more about lines and angles you may visit:

brainly.com/question/6636431

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2 years ago
Can someone help me with this?Can someone help me with this!!!
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Step-by-step explanation:

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6 0
3 years ago
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