All categories

3 years ago

Need help on this ASAP! It’s due right now someone please help

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

3 0

Answer:

Part a would be "C" and part b would be "C" I believe

Step-by-step explanation:

(a):it is a constant speed, then decline, then back to constant.

(b):constant then he gets slower.

You might be interested in

An auto dealership wants to know the average amount of money its customers can spend on a car. The dealership surveys 50 random

KonstantinChe [14]

Hi I would have to say 350

6 0

2 years ago

Read 2 more answers

wo quantities are related, as shown in the table: x y 2 2 4 5 6 8 8 11 Which equation best represents the relationship?

balandron [24]

These quantities are related linearly with slope
3/2. without knowing the answer choices I can only give you examples of equations that fit

y-2=3/2(x-2). or y=3/2(x) -1

etc

7 0

3 years ago

What is the slope-intercept from equation of the line that passes through (5,7)and(8,22)?

elena55 [62]

y=5X+32

I hope this helps!

6 0

3 years ago

How many times can 34 go in 136

Art [367]

It can go into 136 4 times. Just do 136 divided by 34. It's even enough to go into it.

5 0

3 years ago

Read 2 more answers

A certain company sends 40% of its overnight mail parcels by means of express mail service A1. Of these parcels, 4% arrive after

Harrizon [31]

Answer:

(a) The probability that a randomly selected parcel arrived late is 0.026.

(b) The probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(d) The probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

Step-by-step explanation:

Consider the tree diagram below.

(a)

The law of total probability sates that: $P(A)=P(A|B)P(B)+P(A|B')P(B')$

Use the law of total probability to determine the probability of a parcel being late.

$P(L)=P(L|A_{1})P(A_{1})+P(L|A_{2})P(A_{2})+P(L|A_{3})P(A_{3})\\=(0.04\times0.40)+(0.01\times0.50)+(0.05\times0.10)\\=0.026$

Thus, the probability that a randomly selected parcel arrived late is 0.026.

(b)

The conditional probability of an event A provided that another event B has already occurred is:

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

Compute the probability that a parcel was late was being shipped through the overnight mail service A₁ as follows:

$P(A_{1}|L)=\frac{P(L|A_{1})P(A_{1})}{P(L)} \\=\frac{0.04\times 0.40}{0.026} \\=0.615$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{2}|L)=\frac{P(L|A_{2})P(A_{2})}{P(L)} \\=\frac{0.01\times 0.50}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{3}|L)=\frac{P(L|A_{3})P(A_{3})}{P(L)} \\=\frac{0.05\times 0.10}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

4 0

3 years ago