What is the value of 0.1562 rounded to the nearest hundredth place?

Fred spent half his allowance on going to the movies he then washed the family car for six dollars he now has eleven dollars how

kotykmax [81]

Answer:

He gets $10 for his weekly allowance.

Step-by-step explanation:

Let x represent the amount that Fred gets for his allowance weekly.

Fred spent half his allowance on the movies. This means that the total amount that he spent on the movies is x/2. The amount that he is left with would be

x - x/2 = x/2

He washed the family car for six dollars. This means that the total amount that he is left with would be

x/2 + 6

if he now has eleven dollars, it means that

x/2 + 6 = 11

x/2 = 11 - 6 = 5

x = 2 × 5 = $10

4 0

3 years ago

John has 2456 pennies in his coin collection he has the same number of pennies in each of the three boxes estimate to the neares

Keith_Richards [23]

If I read correctly, 2456 pennies needs to be divided simply by 3 then rounded to the nearest hundredth. So you would do 2456/3 3 goes into 24 how many times? Then 3 goes into 5 how many times, then continue the pattern. Once you've gotten a decimal to the thousandth, round the number to the hundredth and there you go

5 0

3 years ago

a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-

Tresset [83]

Answer:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

$M = \frac{1}{2}(Lower + Upper)$

Where

$Lower \to$ Lower class interval

$Upper \to$ Upper class interval

So, we have:

Class 63-65:

$M = \frac{1}{2}(63 + 65) = 64$

Class 66 - 68:

$M = \frac{1}{2}(66 + 68) = 67$

When the computation is completed, the frequency distribution will be:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

$\bar x = 70.2903$

$\sigma = 3.5795$

<em>See attachment for result of 1-VarStats</em>

8 0

3 years ago

When you are solving a system of equations by graphing, graph the lines and look for the point of __________________.

solmaris [256]

Intersection

Where the graph line matches with which column of graph...... take a line from that place to the axis to identify value on that point of intersection

Hope it helped !!

7 0

3 years ago

Read 2 more answers

Can someone plz help me on this plz I beg u plz

JulsSmile [24]

<h3>Answer: 25w+200 > 750</h3>

==========================================================

Explanation:

He starts off with 200 cards. Then he adds on 25w more cards for each week (w). Overall, he'll have 200+25w cards

We can think of it like this:

After 1 week, he adds on 25*1 = 25 cards
After 2 weeks, he adds on 25*2 = 50 cards total
After 3 weeks, he adds on 25*3 = 75 cards total
After 4 weeks, he adds on 25*4 = 100 cards total, and so on.
After w weeks, he adds on 25w cards total

So that's another way to see where the 25w comes from.

The expression 200+25w is the same as 25w+200. This is because we can add two numbers in any order.

------------

Since he wants to know when he'll have more than 750 cards, this means we set 25w+200 greater than 750.

That's how we get to the answer of 25w+200 > 750

Notice how there isn't a line under the inequality sign. We aren't using the "greater than or equal to" symbol here. We want to know when the cards gets over 750, but we don't want to know when it's equal to 750.

5 0

3 years ago