3 years ago

Please help me with this question

Mathematics

1 answer:

Daniel [21]3 years ago

8 0

Answer:

1/2

Step-by-step explanation:

if you look at a unit circle, sin(\pi/6) is $\sqrt{3}/2$ so cos of (\pi/6/2) would be \pi/3, and cos of (\pi/3) is 1/2

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4 years ago

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3 years ago

NEED SOME HELP HERE!!

Stolb23 [73]

Answer:

6 and 8

Step-by-step explanation:

Pythagorean theorem: a² + b² = c²

Given this,

(3x)² + (4x)² = 10²

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5 0

3 years ago

Find the solution of 3 times the square root of the quantity of x plus 6 equals negative 12, and determine if it is an extraneou

Anna35 [415]

For this case we have the following equation:
$3 \sqrt{x+6}=-12$
Rewriting we have:
$\sqrt{x+6}= \frac{-12}{3}$
$\sqrt{x+6}=-4$
We raise both members of the equation to the square:
$(\sqrt{x+6})^2=(-4)^2$
Rewriting we have:
$x+6=16$
$x=16-6$
$x=10$
It's a extraneous solution because equality is not met by substituting x = 10 in the original equation:
$3 \sqrt{10+6}=-12$
$3 \sqrt{16}=-12$
$3(4)=-12$
$12=-12$
Answer:
The solution is:
$x=10$
It's a extraneous solution

6 0

3 years ago

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DiKsa [7]

I DONT KNOW JUST STRAT WITH THE BEGGINIG OF THE SENTENCE

5 0

3 years ago

Read 2 more answers