(DVD player+ TV)= 49.36+705.20= 754.56
754.56/12=62.88
She will have to pay $62.88 each time
Answer: n=c-d
Step-by-step explanation: n+d=c so n=c-d
Answer:
a) Statistic.
b) The population proportion is expected to be between 0.29 and 0.31 with a 94% degree of confidence.
Step-by-step explanation:
a) The proportion of 30% is a statistic, as it is a value that summarizes data only from the sample taken in the study from USA Today. Other samples may yield different proportions.
b) We can use the statistic to estimate a confidence interval for the parameter of the population.
The standard error for the proportion is calculated as:
![\sigma_p=\sqrt{\dfrac{p(1-p)}{N}}=\sqrt{\dfrac{0.3\cdot 0.7}{7335}}=\sqrt{2.83\cdot10^5}= 0.00535](https://tex.z-dn.net/?f=%5Csigma_p%3D%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7BN%7D%7D%3D%5Csqrt%7B%5Cdfrac%7B0.3%5Ccdot%200.7%7D%7B7335%7D%7D%3D%5Csqrt%7B2.83%5Ccdot10%5E5%7D%3D%200.00535)
The margin of error is 0.01. We can use this value to determine the level of confidence that represents.
The formula for the margin of error is:
![E=z\cdot \sigma_p=0.01\\\\z\cdot 0.0535=0.01\\\\z=1.87](https://tex.z-dn.net/?f=E%3Dz%5Ccdot%20%5Csigma_p%3D0.01%5C%5C%5C%5Cz%5Ccdot%200.0535%3D0.01%5C%5C%5C%5Cz%3D1.87)
This z-value, according to the the standard normal distribution, corresponds to a confidence interval of 94%.
The interval for this margin of error is:
![p-E\leq \pi \leq p+E\\\\0.30-0.01\leq \pi \leq 0.30+0.01\\\\0.29\leq \pi \leq 0.31](https://tex.z-dn.net/?f=p-E%5Cleq%20%5Cpi%20%5Cleq%20p%2BE%5C%5C%5C%5C0.30-0.01%5Cleq%20%5Cpi%20%5Cleq%200.30%2B0.01%5C%5C%5C%5C0.29%5Cleq%20%5Cpi%20%5Cleq%200.31)
Then, we can conclude that the population proportion is expected to be between 0.29 and 0.31 with a 94% degree of confidence.
Answer:
Respect Girls!
Don't Post Unwanted things.
I know u r from India.
In Indian Server it is common.
So we know that the swimming pool is 15 by 7 meters wide.
15 times 7 is 105.
Now, a tile costs $6 and covers 1 square meter.
So, we should multiply 105 by 6, which would give us 630.
So, if I'm correct, the answer should be that it costs him $630 to install the tiles on the swimming pool.
(sorry if I'm incorrect)