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miv72 [106K]
3 years ago
10

5% of what number is 63?

Mathematics
1 answer:
masha68 [24]3 years ago
6 0
To find the percentage of a number, you take the percent - 5% - and change it to a decimal by moving the percent over 2 times to the left and multiplying it by the number. So...

.05 x 63
= 3.15

Answer: 5% of 63 is 3.15
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What is 73 divided by 8 equal in remainder???
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9 remainder 1

Step-by-step explanation:

Not sure but uh... 73/8=9 remainder 1.

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2 years ago
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If p(x) = x2 – 1 and 4(x) = 5(x-1), which expression is equivalent to (p -9)(x)?
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Y ≤ -2x + 4. What points satisfy the inequality?
MrRissso [65]
​Subtract 4 from both sides
y−4≤−2x

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<span>x  ≤  −   y−4/2<span><span><span><span><span>​​</span></span></span>​​





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3 years ago
How is the graph of y=2(3)^x+1 translated from the graph of y = 2(3)^x
umka2103 [35]

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7 0
3 years ago
2x² - 5x+1 has roots alpha and beta. Find alpha⁴+beta⁴ without solving the equation.
shepuryov [24]

Answer:

Step-by-step explanation:

\alpha+\beta=\dfrac{5}{2} \\\\\alpha*\beta=\dfrac{1}{2} \\\\\alpha^2+\beta^2=\dfrac{21}{4} \ (see\ previous\ post)\\\\(\alpha+\beta)^4=\dfrac{625}{16} \\\\=\alpha^4+\beta^4+4*\alpha^3*\beta+6*\alpha^2*\beta^2+4*\alpha*\beta^3\\\\=\alpha^4+\beta^4+4*(\alpha*\beta)(\alpha^2+\beta^2)+6*\alpha^2*\beta^2\\\\\alpha^4+\beta^4=(\alpha+\beta)^4-4*(\alpha*\beta)(\alpha^2+\beta^2)-6*\alpha^2*\beta^2\\\\= \dfrac{625}{16} -4*\dfrac{1}{2} *\dfrac{21}{4} -6*(\dfrac{1}{2})^2 \\\\

= \dfrac{625}{16}- \dfrac{168}{16}-\dfrac{24}{16}\\\\\\= \dfrac{433}{16}

7 0
2 years ago
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