Please help!! And show work please.
1 answer:
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Answer:
- see attached for a graph
- 2006: 8,194
- no x-intercepts
- horizontal asymptote: y = 10,350; no vertical asymptotes
- 2015: 10,084
- no information on Exercise 5
Step-by-step explanation:
<h3>a)</h3>The graph is attached
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<h3>b)</h3>The value for 2006 is shown in the table for x=6: 8,194.
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<h3>c)</h3>The graph does not cross y=0. It has a minimum of about 7392.
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<h3>d)</h3>The denominator is never zero, so there are no vertical asymptotes. The horizontal asymptote is the ratio of the x^2 coefficients, 414/0.04 = 10,350.
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<h3>e)</h3>The value of the function for x=15 is 10,084. The number of women in the Marines in 2015 is modeled as 10,084.
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<h3>f)</h3>No information is provided regarding Exercise 5 or its answer.
Answer:
See explanation and results below.
Step-by-step explanation:
We have the following data:
Age (yr) when award was won Frequency 25-34 31 35-44 36 45-54 12 55-64 4 65-74 6 75-84 1 85-94 2
If we order the data we got the following result. We assume that the midpoint is given by:
The
And the limits are given by the lower and upper limit.
L.Limit U.Limit Class W Midpoint Frequency Limits
25 34 34-25=9 29.5 31 [25-34]
35 44 44-35=9 39.5 36 [35-44]
45 54 54-45=9 49.5 12 [45-54]
55 64 64-55=9 59.5 4 [55-64]
65 74 74-65=9 69.5 6 [65-74]
75 84 84-75=9 79.5 1 [75-84]
85 94 94-85=9 89.5 2 [85-94]