Answer:
Second hand will turn through 74π radians.
Step-by-step explanation:
There are 37 minutes left in the class. We need to find by how much angle will the second hand turn before the end of the class.
When a second hand completes one full rotation along the clock it covers 360 degrees and completes 60 seconds.
This means:
In 60 seconds, the second hand turns by 360 degrees
Since, 60 seconds = 1 minute, we can write:
In 1 minute, the second hand turns = 360 degrees
360 degrees is equal to 2π radians. So,
In 1 minute, the second hand turns = 2π radians
Multiplying both sides by 37 gives us:
In 37 minutes, the second turns = 2π radians x 37 = 74π radians
3^5) (x + 2)^(3/2) + 3 = 27
<span>(x + 2)^(3/2) = 24 / 243 </span>
<span>x + 2 = [ 24 / 243 ]^(2/3) </span>
<span>x + 2 = [ 8 / 81 ]^(2/3) </span>
<span>x = [ 4 / 81^(2/3) ] - 2 =-1.786
the answer is x=-1.786</span>
Answer:
19°
Step-by-step explanation:
I have attached an image showing this elevation.
From the image, let's first find the angle A by using cosine rule.
Thus;
8.1² = 5.5² + 13.1² - 2(5.5 × 13.1)cos A
65.61 = 30.25 + 171.61 - 144.1cos A
144.1cos A = 171.61 + 30.25 - 65.61
144.1cosA = 136.25
cosA = 136.25/144.1
cosA = 0.9455
A = cos^(-1) 0.9455
A = 19°
Answer:
y = -5x + 6
Step-by-step explanation:
General equation of a line : y = mx + c......where c is intercept
To find m pick any two points..
(-2, 16) and (-1, 11)
Using (y - y¹) / (x - x¹)
(11 - 16) / (-1 - [-2]) = -5 / 1
= -5
To find c sub with any point for (x, y) and m
using (2, -4)
y = mx + c
-4 = -5(2) + c
-4 = -10 + c
6 = c
Input the values of m and c in the general equation without x and y
; y = -5x + 6
<span>
</span><span>
Depending on the value of 't' and 'u', the numerical value of that expression
could have almost anything for factors.
For example, if 't' happens to be 3 and 'u' happens to be 10, then 6tu = 180,
and the factors of 6tu are
1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, and 180.
But that would only be temporary ... only as long as t=3 and u=10.
The only factors you can always count on, that don't depend on the values
of 't' and 'u', are
1, 6, t, u, 6t, 6u, tu, and 6tu .
</span>
