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N76 [4]
3 years ago
11

What is the value of the x ? x + x + x = 56

Mathematics
1 answer:
umka21 [38]3 years ago
6 0
X = 56 divided by 3 = 18.6
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What is the value of x?<br><br> 27(x+4)=−6<br><br><br> −35<br><br> −25<br><br> 25<br><br> 35
Oksanka [162]

x = -38/9 !!!


27(x+4)=−6

Step 1: Simplify both sides of the equation.

27(x+4)=−6

(27)(x)+(27)(4)=−6 (Distribute)

27x+108=−6

Step 2: Subtract 108 from both sides.

27x+108−108=−6−108

27x=−114

Step 3: Divide both sides by 27.

27x/27=−114/27

x=−389

6 0
3 years ago
What does -3 1/6+6 2/3 equal
Step2247 [10]

Answer:

3½

Step-by-step explanation:

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3 + 4/6 - 1/6

3 + 3/6

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6 0
3 years ago
Read 2 more answers
In calculus, we went over the subject of implicit differentiation. I feel pretty solid on how to do it, except when they give th
babymother [125]
The same way.

\dfrac{dy}{dx} means it's derivative of function y with respect to x

\dfrac{dx}{dt} means it's derivative of function x with respect to t

\dfrac{dx}{dy} means it's derivative of function x with respect to y


7 0
3 years ago
The clutch linkage on a vehicle has an overall advantage of 24:1. If the pressure plate applies a force of 504lb,how much force
Anon25 [30]

Answer:

the force that must be applied by the driver to release the clutch is 21 lb

Step-by-step explanation:

Data provided:

clutch linkage on a vehicle has an overall advantage = 24:1

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Now,

the advantage ratio is given as:

advantage ratio = \frac{\textup{Force applied by the pressure plate}}{\textup{Force applied by the driver}}

on substituting the respective values, we get

\frac{\textup{24}}{\textup{1}}  = \frac{\textup{504 lb}}{\textup{Force applied by the driver}}

or

Force applied by the driver to release the clutch = \frac{\textup{504 lb}}{\textup24}}

or

Force applied by the driver to release the clutch = 21 lb

Hence,

the force that must be applied by the driver to release the clutch is 21 lb

6 0
3 years ago
Write 250 in standard form
UNO [17]
<span>To start, this has a value in the hundreds position: 200. This would be translated into "n * 10^2" in standard notation. We also see that we're working with more than 2 * 100 in this case, so the value that gives an "n" between 1 and 10 to set as a multiplier is 2.5. This gives "2.5 * 10^2" as a proper form.</span>
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3 years ago
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