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Reil [10]
2 years ago
5

Please help me with this problem ​

Mathematics
1 answer:
kow [346]2 years ago
6 0

Answer:

what is the question, all I see is a picture

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a man wanted to paint a cylinder gas tank. What amount of surface area will need to be covered if it had a radius of 14 inches a
Over [174]

Answer:

224

Step-by-step explanation:

  1. in a cylinder  the  only sides that would actually count is the top and bottom
  2. you would multiply the top and bottom.
  3. 14 x 16 = 224
  4. if I'm wrong let me know
5 0
3 years ago
Is the relationship linear?
lianna [129]
Yes it is linear yes
5 0
2 years ago
Writetwo ways you could use to find 5+8
Igoryamba

5+8=13

or

13-8=5

Hope this helps!

5 0
2 years ago
Read 2 more answers
the value of c guaranteed to exist by the Mean Value Theorem for V(x) = x² in the interval [0, 3] is...? a) 1 b) 2 c) 3/2 d) 1/2
lilavasa [31]

Answer:  c) \dfrac{3}{2} .

Step-by-step explanation:

Mean value theorem : If f(x) is defined and continuous on the interval [a,b] and differentiable on (a,b), then there is at least one number c in the interval (a,b) (that is a < c < b) such that

\begin{displaymath}f'(c) = \frac{f(b) - f(a)}{b-a} \cdot\end{displaymath}

Given function : f(x) = x^2

Interval : [0,3]

Then, by the mean value theorem, there is at least one number c in the interval (0,3) such that

f'(c)=\dfrac{f(3)-f(0)}{3-0}\\\\=\dfrac{3^2-0^2}{3}=\dfrac{9}{3}\\\\=3

\Rightarrow\ f'(c)=3\ \ \ ...(i)

Since f'(x)=2x

then, at x=c, f'(c)=2c\ \ \ ...(ii)

From (i) and (ii), we have

2c=3\\\\\Rightarrow\ c=\dfrac{3}{2}

Hence, the correct option is c) \dfrac{3}{2} .

4 0
3 years ago
Could use the help! thanks again!
love history [14]

Answer:

Beth is incorrect.

It is a translate to the right 5 units and up 1 unit.

When we solve x-5=0 we get x=5, not x=-5 which says we go right 5 units.

When we plug in 5 into the expression for g, we get 1 which means go up 1 as well.

Step-by-step explanation:

So g(x)=\sqrt{x-5}+1 is actually a translated 5 units and up 1 unit. Why?

Let's take there point (0,0) and figure out what the new point is on the translated graph.

We need to figure out when the inside of our square root for g is 0.  This is where the graph of g will start at and continue on.

x-5=0 when x=5 ( I added 5 on both sides).

So let's plug in 5 to see what the new point is.

g(5)=\sqrt{5-5}+1

g(5)=\sqrt{0}+1

g(5)=0+1

g(5)=1

So the new graph, g, starts at the point (5,1).

5 0
2 years ago
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