Please help me with this problem
1 answer:
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Answer: c) .
Step-by-step explanation:
Mean value theorem : If f(x) is defined and continuous on the interval [a,b] and differentiable on (a,b), then there is at least one number c in the interval (a,b) (that is a < c < b) such that
Given function :
Interval : [0,3]
Then, by the mean value theorem, there is at least one number c in the interval (0,3) such that
Since
then, at x=c,
From (i) and (ii), we have
Hence, the correct option is c) .
Answer:
Beth is incorrect.
It is a translate to the right 5 units and up 1 unit.
When we solve x-5=0 we get x=5, not x=-5 which says we go right 5 units.
When we plug in 5 into the expression for g, we get 1 which means go up 1 as well.
Step-by-step explanation:
So is actually a translated 5 units and up 1 unit. Why?
Let's take there point (0,0) and figure out what the new point is on the translated graph.
We need to figure out when the inside of our square root for g is 0. This is where the graph of g will start at and continue on.
x-5=0 when x=5 ( I added 5 on both sides).
So let's plug in 5 to see what the new point is.
So the new graph, g, starts at the point (5,1).