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3 years ago

Which of these expressions can you simplify by combining like terms

Mathematics

2 answers:

Tom [10]3 years ago

7 0

Answer:

top right bottom left

Step-by-step explanation:

exis [7]3 years ago

4 0

Answer:

Option 1.

Step-by-step explanation:

Like terms : Two terms are called like terms if they have same variables of same degree.

We need to find the expression that can be simplify by combining like terms .

It means we have to find the expression which contains like terms.

In option 1,

The given expression is

$6d^2+5cd-3dc+8$

In this expression 5cd and -3dc are like terms. On combining like terms we get

$6d^2+(5cd-3dc)+8$

$6d^2+2dc+8$

So, this expression can simplify by combining like terms.

There are no like terms in other three expressions.

Therefore, the correct option is 1.

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A specifiic shade of green glaze requires 5 parts blue to 3 parts yellow. A glaze mixture contains 25 quarts of blue and 9 quart

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3 years ago

Read 2 more answers

Rationalize the denominator of 4/14 root 2?

Katarina [22]

First of all, you can simplify the 4 at the numerator and the 14 at the denominator (they're both multiple of 2):

$\dfrac{4}{14\sqrt{2}} = \dfrac{2\cdot 2}{2\cdot 7\cdot\sqrt{2}} = \dfrac{2}{7\sqrt{2}}$

Now, rationalize a denominator means that you have to get rid of the square root, in order to have an integer denominator.

To do so, remember that you can always multiply any number by 1 without changing its value, and you can always think of 1 as a fraction where numerator and denominator are equal:

$\dfrac{2}{7\sqrt{2}} = \dfrac{2}{7\sqrt{2}}\cdot 1 = \dfrac{2}{7\sqrt{2}} \cdot \dfrac{\sqrt{2}}{\sqrt{2}} = \dfrac{2\sqrt{2}}{7\cdot 2} = \dfrac{\sqrt{2}}{7}$

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3 years ago

Write the slope-intercept form of the equation that passes through the point (-3, 5) and is perpendicular to the line y = 1/5x +

aleksley [76]

Answer:

Step-by-step explanation:

$\text{Let}\\\\k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\=========================$

$\text{We have}\ y=\dfrac{1}{5}x+10\to m_1=\dfrac{1}{5}\\\\\text{Therefore}\ m_2=-\dfrac{1}{\frac{1}{5}}=-5.\\\\\text{Put the value of a slope and the coordinates of the point (-3, 5)}\\\text{to the equation}\ y=mx+b:\\\\5=-5(-3)+b\\5=15+b\qquad\text{subtract 15 from both sides}\\-10=b\to b=-10\\\\\text{Finally:}\\\\y=-5x-10$

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3 years ago

What is the domain of F(x)

nydimaria [60]

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3 years ago