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IrinaVladis [17]
3 years ago
13

A recipe for cake needs 3/4 if a cup of milk. you are making 1/2 of the recipe.his much milk do you need

Mathematics
2 answers:
IgorC [24]3 years ago
6 0
We need 1/2 of 3/4. So it'll look like this: 
(3/4)/2

So! We need to work with this fraction inside a fraction. To do so take the denominator and flip it. Then multiply across. 

3/4 * 1/2

3/8

Or you can think of it like this!

3/4 is 0.75. 

0.75/2 is 0.375 or in fraction form 3/8.

You can find the fraction form of 0.375 like a so... : 
(Each time I divide both the numerator and denominator by 5)

375/1000
75 / 200
15 / 40
3 / 8
r-ruslan [8.4K]3 years ago
4 0
I would say it's 3/8 of a cup because if you multiply 3/4 by 2 it would be 6/8. It's the same amount but just a different measurement. Now just take 3 away from 6/8 and you have 3/8 which is half of 3/4.
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Find the mass of the solid paraboloid Dequals=​{(r,thetaθ​,z): 0less than or equals≤zless than or equals≤8181minus−r2​, 0less th
Lubov Fominskaja [6]

Answer:

M = 5742π  

Step-by-step explanation:

Given:-

- Find the mass of a solid with the density ( ρ ):

                             ρ ( r, θ , z ) = 1 + z / 81

- The solid is bounded by the planes:

                             0 ≤ z ≤ 81 - r^2

                             0 ≤ r ≤ 9

Find:-

Find the mass of the solid paraboloid

Solution:-

- The mass (M) of any solid body is given by the following triple integral formulation:

                           M = \int \int \int {p ( r ,theta, z)} \, dV\\\\

- We can write the above expression in cylindrical coordinates:

                           M = \int\limits\int\limits_r\int\limits_z {r*p(r,theta,z)} \, dz.dr.dtheta \\\\M = \int\limits\int\limits_r\int\limits_z {r*[ 1 + \frac{z}{81}] } \, dz.dr.dtheta\\\\

- Perform integration:

                           M = \int\limits\int\limits_r{r*[ z + \frac{z^2}{162}] } \,|_0^8^1^-^r^2 dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{(81-r^2)^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{6561 -162r + r^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + 40.5 -r +\frac{r^2}{162} ] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{[ 121.5r-r^2 -\frac{161r^3}{162} ] } \, dr.dtheta\\\\

                           M = 2*\int\limits_0^\pi {[ 121.5r^2-r^3 -\frac{161r^4}{162} ] } |_0^6 \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 121.5(6)^2-(6)^3 -\frac{161(6)^4}{162} ] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 4375-216 -1288] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 2871] }  \, dtheta\\\\M = 5742\pi  kg              

- The mass evaluated is M = 5742π                      

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Arthur is interested in the effects of sleep deprivation usage on number of calories consumed. He asks a group of 20 college stu
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

2(500l + 500b)

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8 0
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