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Sunny_sXe [5.5K]
2 years ago
8

Need help with this

Mathematics
1 answer:
Marrrta [24]2 years ago
7 0

Answer:

law of cosines states c^2=a^2+b^2-2abc

b^2=26^2+24^2-2(26×24)cos 134°

b^2=676+576-1248cos134°

cos134= -0.6946

b^2=1252-12(-0.6946)

12×(-0.6946)= -8.3352

b^2=1252-(-8.3352)

b^2=1252+8.3352

b^2=1260.33

b=√1260.33

b=35.50

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Zina [86]

Answer:

-45

Step-by-step explanation:

(4.5)(5)(-2)=-45

therefore the answer would be the fourth option which is -45

3 0
3 years ago
I keep getting this wrong, please help me
Marat540 [252]

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Step-by-step explanation:

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Is a soup bowl a gallon quart pint or cup​
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2 years ago
Karen spends $450 on monthly bills. Of this total amount, 12% is for phone service, 1/10 is for internet service, and 2/9 is for
finlep [7]
12%= 0.12 = 12/100 = 108/900
1/10 = 90/900
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108/900 + 90/900 + 200/900 = 398/900 used

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Karen has $251 for food
4 0
3 years ago
Determine if b is a linear combination of a1 a2, and a3. a1 = [ 1 -2 0 ], a2 = [ 0 1 3 ], a3 = [ 6 -6 18 ], b = [ 2 -2 6 ] Choos
marysya [2.9K]

Answer: Vector b is not a linear combination

Step-by-step explanation:

First of all we put the vectors in terms of different variables, such as:

a1(1,-2,0)=(a,-2a,0);

a2(0,1,3)=(0,b,3b);

a3(6,-6,18)=(6c,-6c,18c);

To know that a vector is a linear combination we need to express it like a sum of other different vectors.

(2,-2,6)=(a,-2a,0)+(0,b,3b)+(6c,-6c,18c)

(2,-2,6)=(a+0+6c,-2a+b-6c,0+3b+18c)

We express this sum like a system of equations.

a+6c=2

-2a+b-6c=-2

3b+18c=6

We solve this system of equations and we can note that the system don't have a solution, so the vector b is not a linear combination of a1, a2, and a3.

8 0
3 years ago
Read 2 more answers
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