Question

The coordinates of A, B, and C in the diagram are A(p,4), B(6,1), and C(9,q). Which equation correctly relates p and q?

Answer 1

ANSWER

$p + q= 7$

EXPLANATION

We determine the slope of each line using the slope formula;

$m = \frac{y_2-y_1}{x_2-x_1}$

The slope of BC is

$= \frac{ q - 1}{9 - 6}$

$\frac{ q - 1}{3}$

The slope of AB is

$= \frac{1 - 4}{6 - p}$

$= - \frac{3}{6 - p}$

The two lines are perpendicular so the product of their slopes is -1.

$- \frac{3}{6 - p} \times \frac{ q - 1}{3} = - 1$

This implies that,

$\frac{q - 1}{6 - p} = 1$

$q - 1=6 - p$

$q + p = 6 + 1$

$p + q= 7$

.

Answer 2

Answer: maybe 10

Step-by-step explanation: