I’m having trouble on 10-11, if you can find the answer. Thank you!
1 answer:
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Answer:
92
Step-by-step explanation:
Lab Scores are 84, 81, and 93
Test Scores are 89 and 94
Each lab counts once and each test counts as two labs. At the end of the semester there is a final lab that counts as three regular labs.
Total Number of Labs= (3X1)+(2X2)+(1X3) =3+4+3 =10
To recieve an A(90), the average of her scores must be 90.
Let her final lab score =b
Refer to the attached diagram
Total Score=624+3b
For her average =90
Cross multiplying
624+3b =90 X 10
624+3b =900
3b =900-624
3b =276
Dividing both sides by 3
b= 92
She must score 92 in her final lab to receive an A.
Answer:
35.6 yd²
Step-by-step explanation:
Area of ∆UVW can be solved if we know the lengths of 2 sides and their included angle.
We are Given just 1 side, UV (w). Use the law of sines to find UW (v).
Thus:
W = 137°
w = 19 yd
V = 180 - (137 + 22) = 21° => sum of triangle
v = ??
Plug in the values and solve for v
Multiply both sides by sin(21)
(approximated)
Find area of ∆UVW:
Area = ½*UV*UW*sin(U)
Area = ½*v*w*sin(U)
= ½*10*19*sin(22)
Area = 35.6 yd² (to nearest tenth)