The binomial coefficients are 1,5,10,10,5,1 (5/0, 5/1, 4/2, 3/3, 2/4, 1/5)
x^5-25x^4+250x^3-1250x^2+3125x-3125
Answer:
The probability of of a randomly chosen student being exactly 21 years old.
= 1.293
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given Population size n = 500</em>
<em>Mean of the Population = 20 years and 6 months</em>
<em> = </em>
<em></em>
<em>Standard deviation of the Population = 2 years</em>
Let 'X' be the range of ages of the students on campus follows a normal distribution
Let x =21


<em>The probability of a randomly chosen student being exactly 21 years old.</em>
<em>P( Z≤21) = 0.5 + A( 0.2) </em>
= 0.5 +0.793
= 1.293
Uv al dt or trace mcsorely
Answer:
Final answer is c=-7.
Step-by-step explanation:
Given equation is
.
Now question says that Misha wrote the quadratic equation 0=-x2+4x-7 in standard form. Now we need to find about what is the value of c in her equation.
We know that standard form of quadratic equation is given by
.
compare given equation with the standard form, we find that -7 is written in place of +c
so that means +c=-7
or c=-7
Hence final answer is c=-7.
All our answers lie in the above statement.
Confidence Level:
The creator claims that 9 out 10 students will have the average score in the said range. Or in other words we can say that the creator is 90% confident about the result of the field test. So the confidence level is 90%.
Margin of Error:
The average score lies within 4% of 70%. This means the margin of error is 4% i.e. the average scores can deviate from 70% by 4% .
Confidence Interval:
Lower Limit = 70% - 4% = 66%
Upper Limit = 70% + 4% = 74%
Interpretation:
The exam creator is 90% confident that the average scores of seniors will be between 66% and 74%.