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belka [17]
3 years ago
9

Round off measurement 0.0003095 to 3 significant figures

Chemistry
2 answers:
KengaRu [80]3 years ago
8 0
You could also say 3.10 x 10^-4
Novay_Z [31]3 years ago
3 0
0.000310 is the answer 
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3 years ago
Which of the following sets represents a pair of isotopes?
son4ous [18]
The correct option is A,
Isotopes are atoms of an element, which have the same number of protons but different number of neutrons in the nucleus of the atom. Thus, isotopes have the same atomic number but different mass number.
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5 0
4 years ago
From Young's experiment, how does the frequency of light affect the number of lines observed?
Marina CMI [18]

Answer : (C) "Higher frequencies have larger spaces between lines".

Explanation:

In Young's experiment, the condition for constructive interference is given by :

dsin\theta=n\lambda.........(1)

n is order or number of lines observed

d is distance between slits

\theta is the angle between the path and the line from screen to the slits.

We also know that, c=\nu \lambda

or

\lambda=\dfrac{c}{\nu}

where,

c is the speed of light

\nu is frequency

\lambda is wavelength

So, equation (1) turns into

dsin\theta=n\dfrac{c}{\nu}

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So,

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3 0
3 years ago
Read 2 more answers
Which sentence best describes an igneous intrusion
Ulleksa [173]
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5 0
4 years ago
Read 2 more answers
A 48.0g sample of quartz, which has a specific heat capacity of 0.730·J·g−1°C−1, is dropped into an insulated container containi
Butoxors [25]

Answer:

The equilibrium temperature of the water is 26.7 °C

Explanation:

<u>Step 1:</u> Data given

Mass of the sample quartz = 48.0 grams

Specific heat capacity of the sample = 0.730 J/g°C

Initial temperature of the sample = 88.6°C

Mass of the water = 300.0 grams

Initial temperature = 25.0°C

Specific heat capacity of water = 4.184 J/g°C

<u>Step 2:</u> Calculate final temperature

Qlost = -Qgained

Qquartz = - Qwater

Q =m*c*ΔT

Q = m(quartz)*c(quartz)*ΔT(quartz) = -m(water) * c(water) * ΔT(water)

⇒ mass of the quartz = 48.0 grams

⇒ c(quartz) = the specific heat capacity of quartz = 0.730 J/g°C

⇒ ΔT(quartz) = The change of temperature of the sample = T2 -88.6 °C

⇒ mass of water = 300.0 grams

⇒c(water) = the specific heat capacity of water = 4.184 J/g°C

⇒ ΔT= (water) = the change in temperature of water = T2 - 25.0°C

48.0 * 0.730 * (T2-88.6) -300.0 * 4.184 *(T2 - 25.0)

35.04(T2-88.6) = -1255.2 (T2-25)

35.04T2 -3104.544 = -1255.2T2 + 31380

1290.24T2 = 34484.544

T2 = 26.7 °C

The equilibrium temperature of the water is 26.7 °C

8 0
3 years ago
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