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Mademuasel [1]
3 years ago
6

A carbon-carbon triple bond is found in a molecule of

Chemistry
1 answer:
Masteriza [31]3 years ago
5 0

A triple bond is a type of covalent bond. It involves a sigma bond and two pi bonds (each bond involves 2 electrons). A carbon atom is capable of 4 bonds...a carbon-carbon triple bond is found in all alkynes.


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Are inic bonds formed when electrons are equally or unequally shared
lisabon 2012 [21]

The electrons are unequally shared. The electronegative element receives the electrons from the electropositive one.

8 0
3 years ago
A solution containing a mixture of metal cations was treated with dilute HCl and no precipitate formed. Next, H2S was bubbled th
erica [24]

Answer:

Explanation:

  Ions which will  be definitely  absent -

Ag⁺ , Hg₂⁺ , Pb⁺², because their chlorides are insoluble in water.

Ba⁺² ,Ca⁺² because their carbonates are insoluble in water,

Ions which will be definitely present  

Cu⁺² , Pb⁺² . Hg⁺² , Sb⁺³ , Sn⁺² , because their sulphides are insoluble at pH = 8.

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5 0
3 years ago
10.
Andru [333]

Answer: 1.8 moles Fe and 2.7 moles CO_2 are produced.

Explanation:

The balanced chemical reaction is:

Fe_2O_3+3CO\rightarrow 2Fe+3CO_2  

According to stoichiometry :

3 moles of CO require 1 mole of Fe_2O_3

Thus 2.7 moles of CO will require=\frac{1}{3}\times 2.7=0.9moles  of Fe_2O_3

Thus CO is the limiting reagent as it limits the formation of product and Fe_2O_3 is the excess reagent.

As 3 moles of CO give = 2 moles of Fe  and 3 moles of CO_2

Thus 2.7 moles of CO will give =\frac{2}{3}\times 2.7=1.8moles  of Fe  and \frac{3}{3}\times 2.7=2.7moles  of CO_2

Thus 1.8 moles Fe and 2.7 moles CO_2 are produced.

7 0
3 years ago
A person's blood type is determined by the presence and absence of specific antigens on the cell membrane. Which of these would
sukhopar [10]

Answer:

C - no antibodies

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5 0
3 years ago
Which element increases its oxidation number in this reaction? 2Na + 2H2O → 2NaOH + H2
sammy [17]

Answer:

Sodium

Explanation:

-Gradpoint

6 0
3 years ago
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