8x^5\left(32\sqrt{2}x^2-\sqrt{2}x^4\right)
Lol
trouble varies directly as distance
lets say t=trouble and d=distance
t=kd
k is constant
given
when t=20, and d=400
find k
20=400k
divide by 400 both sides
1/20=k
t=(1/20)d
given, d=60
find t
t=(1/20)60
t=60/20
t=3
3 troubles
Y=x+3
-3x+3(x+3)=4
-3x+3x+9=4
9=4
Since this statement is false, there are no ordered pair solutions to this problem.
Y=4
How?
When they say directly you should multiply the x and y together. You would get -24, now using that number divide -24 by the new x(-6) you would get 4.
