Determine the indicated side length of the golden rectangle. round your answer to the nearest hundreth....

The height and length of a right rectangular prism are each 12 cm. The surface area of the prism is

RideAnS [48]

Answer:

99

Step-by-step explanation:

8 0

3 years ago

The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 oun

Ugo [173]

Answer: A) .1587

Step-by-step explanation:

Given : The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 ounces and a standard deviation of 0.20 ounce.

i.e. $\mu=12.30$ and $\sigma=0.20$

Let x denotes the amount of soda in any can.

Every can that has more than 12.50 ounces of soda poured into it must go through a special cleaning process before it can be sold.

Then, the probability that a randomly selected can will need to go through the mentioned process = probability that a randomly selected can has more than 12.50 ounces of soda poured into it =

$P(x>12.50)=1-P(x\leq12.50)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{12.50-12.30}{0.20})\\\\=1-P(z\leq1)\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.8413\ \ \ [\text{By z-table}]\\\\=0.1587$

Hence, the required probability= A) 0.1587

6 0

3 years ago

How to Find x value: 9-0.75(x+8)-5=-6.5

Dahasolnce [82]

Here's how to find the value of x:

<span>9 - 0.75 ( x + 8 ) - 5 = -6.5 find the difference of 9 - 0.75

</span><span>8.25 ( x + 8 ) - 5 = -6.5 add 5 to both sides
</span>
8.25 ( x + 8 ) = -1.5 distribute 8.25 to x and 8

8.25x + 66 = -1.5 subtract 66 from both sides

8.25x = -67.5 divide both sides by 8.25

x = 18.18181818...... the value of x is 18 2/11

hope this helps

8 0

3 years ago

2+(y5x)

zimovet [89]

.............................

7 0

2 years ago

Add or subtract. Write the result in the form a+bi

STALIN [3.7K]

Number 1: (-1+2i)+(6-9i)

$Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\=\left(-1+6\right)+\left(2-9\right)i\\=5-7i$

Number 2: (3-3i)-(4+7i)

$Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\=\left(3-4\right)+\left(-3-7\right)i\\Refine\\=-1-10i$

Number 3: (-5+2i)+(-2+8i)

$Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\=\left(-5-2\right)+\left(2+8\right)i\\Refine\\=-7+10i$

8 0

3 years ago