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3 years ago

Help me on these questions pleasee.

Mathematics

1 answer:

quester [9]3 years ago

6 0

(b)

The 50 degree angle and angle b are vertical angles, which means they are congruent.

The 50 degree angle and angle c are a linear pair, which means that they are supplementary/add up to 180 degrees.

Angles a and c are vertical angles, which means they are congruent.

a = 130

b = 50

c = 130

(c)

The 90 degree angle and angle b are vertical angles, which means they are congruent.

The 50 degree angle and angle c are vertical angles, which means they are congruent.

The 50 degree angle, 90 degree angle, and angle d all form a line, which means that they are supplementary and add up to 180.

Angle d and angle a are vertical angles, which means they are congruent.

a = 40

b = 90

c = 50

d = 40

(e)

The measure of a circle is 360 degrees. These three angles form a circle, so therefore if we add them all up, they will equal 360 degrees.

3a + 4a + 5a = 360

12a = 360

a = 30

(f)

The measure of a circle is 360 degrees. These four angles form a circle, so therefore if we add them all up, they will equal 360 degrees.

3a + 4a + 5a + 6a = 360

18a = 360

a = 20

Hope this helps!! :)

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Direct mail advertisers send solicitations ("junk mail") to thousands of potential customers in the hope that some will buy the

harina [27]

Answer:

The interval is (.0817, .118).

Step-by-step explanation:

Let's make this interval! The easy way is to go to STAT->TEST->A, 1-prop z-int, but I will show the long way.

1. Conditions

First we must check the conditions.

Randomization condition: The sample is given to be random, so we can assume independence.

Success/failure condition: Both np>10 and nq>10 must be met.

np = 1030(103/1030) = 103 ✓
nq = 1030(927/1030) = 927 ✓

10% condition: The sample cannot be greater than 10% of the population.

10n < N, 10(1030) < 200000 ✓

All conditions are met, so we can use a 1-proportion z-interval to represent the data.

2. Mechanics

Find $\hat{p}$ , the sample proportion.

103/1030 = .1

$\hat{q}$ , then, the probability of not p, is 1 - .1 = .9

Find z* (z star), the critical z-value.

You can do this on your calculator using 2nd->VARS->3 (or you can memorize it - it's 1.96. Winky face.) This is called the invNorm function, that takes the left side area under the normal curve. But what do we plug in to the invNorm function?

invNorm(.975) = 1.96

Plug values into the equation.

$\hat{p}$ ± z* $\sqrt{\frac{\hat{p}\hat{q}}{n} }$

.1 ± 1.96 $\sqrt{\frac{.1*.9}{1030} }$

.1 ± 1.96(.00935)

.1 - .0183 = .0817

.1 + .0183 = .118

(.0817, .118)

3. Conclusion

Based on this sample, we are 95% confident that the proportion of people the company contacts who may buy something is between .0817 and .118. That isn't very likely, but maybe they'll make a little profit!

5 0

3 years ago

Identify the graph of the equation. What is the angle of rotation for the equation? xy=-2.5

Maurinko [17]

Answer:

It is B. hyperbola, 45 degrees.

SteIt is p-by-step explanation:

If we rotate the standard form x^2 - y^2 = 1 through 45 degrees we get xy = 1/2.

xy = -2.5 comes from x^2 - y^2 = -5 being rotated 45 degrees.

3 0

3 years ago

Read 2 more answers

Can someone answer this problem please

TEA [102]

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4 0

3 years ago

21. Tom buys a DVD player on 12 monthly payments. The cash price is $600. He pays

slamgirl [31]

Answer:

Each monthly payment is $ 49.05, and in total Tom paid $ 648.60.

Step-by-step explanation:

Given that Tom buys a DVD player on 12 monthly payments, whose cash price is $ 600, and he pays a 10% deposit and the store charges 9% interest, to determine how much is each payment and the total amount Tom pays for the DVD player the following calculations must be performed:

600 - 600 x 0.1 = 540

540 x 1.09 = 588.6

588.6 / 12 = 49.05

Thus, each monthly payment is $ 49.05, and in total Tom paid $ 648.60.

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3 years ago

Factor 3x^3 - 15x^2 + 18x.

Usimov [2.4K]

Step-by-step explanation:

3 x^3-15x^2+18x 3(x^3-5x^2+6x)

8 0

2 years ago

Help me on these questions pleasee.​

Help me on these questions pleasee.