Hello!
1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?
- <u><em>We have the following data:</em></u>
Vo (initial volume) = 1.00 L
V (final volume) = 473 mL → 0.473 L
Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)
P (final pressure) = ? (in atm)
- <u><em>We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:</em></u>






<u><em>Answer: </em></u>
<u><em>The new pressure of the gas is 2.11 atm </em></u>
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Answer:
c. Kay's rule
Explanation:
Kay's rule -
The rule is used to determine the pseudo reduced critical parameters of mixture , with the help of using the critical properties of the components of a given mixture .
The equation for Kay's rule is as follows ,
PV = Z RT
Where Z = The compressibility factor of the mixture .
Hence from the given options , the correct answer is Kay's rule .
Answer:
Q Line A
A: (a) 0 (b) 20
B: (b) 10 (c) 10
C: (c) 10 (d) 10
D: (d) 10 (e) 13
E: (e) 13 (f) 0
F: (f) 0 (g) 0
a: The velocity is whatever you need to see when you are specifically using a numberline so the answer for a is just 10
b: The velocity for this one is not as easy as the last one, its 7.
Explanation:
When you have a number line and your trying to find a numberline, you just have to subtract the smaller line to the largest number but if you are trying to find the velocity in beetween more than one thane you add the two biggest ones and subtract the smallest one and if you make a wrong move like add the biggest and smalles youll... still get the same answer so it doesnt matter really but its just easier to do the smallest one as the subtracting number just FYI. Happy spring break!
This temperature in units of degree Celsius is..
-78° Celsius
Answer:
6.3 moles
Explanation:
From the balanced equation of reaction:

2 moles of aluminium reacts with 3 moles of chlorine gas to form 2 moles of AlCl3.
Therefore, 1 mole of chlorine will require: 2 x 1/3 = 0.67 mole of aluminium.
Hence, 0.67 mole of aluminium will be needed for 1 mole of chlorine. If 7 moles of aluminium is present, then:
7 - 0.67 = 6.33 moles of aluminium will be left.
To the nearest 0.1, it means 6.3 moles of aluminium will be left.