Solution of 0.25 M is prepared in two steps,
1) Calculate Amount of Solute:
Molar Mass of Solute: 342.3 g/mol
As we know,
Molarity = Moles / 1 dm³
or,
Moles = Molarity × 1 dm³
Putting Values,
Moles = 0.25 mol.dm⁻³ × 1 dm³
Moles = 0.25 moles
Now, find out mass of sucrose,
As,
Moles = Mass / M.mass
or,
Mass = Moles × M.mass
Putting Values,
Mass = 0.25 mol × 342.3 g.mol⁻¹
Mass = 85.57 g
2) Prepare Solution:
Take Volumetric flask and add 85.57 g of sucrose in it. Then add distilled water up to the mark of 1 dm³. Shake well! The solution prepared is 0.25 M in 1 Liter.
Scale is defined as the measurement of unit ranges, that has been corresponds to the measurements.
The units for the measurement of temperature are given as:

<h3>Which scale is used?</h3>
The scale used for the measurement of the freezing is the temperature scale. The temperature is measured in the units of Kelvin, Fahrenheit , and Celsius.
The unit scale for the measurement of freezing of water are
- Freezes at 32 - In the Fahrenheit scale
- Freezes at 0 - In the Celsius scale
- Freezes at 273 - In the Kelvin scale
Learn more about measurement scale, here:
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<h2>
Hello!</h2>
The answer is:
The new volume will be 1 L.

<h2>
Why?</h2>
To solve the problem, since we are given the volume and the first and the second pressure, to calculate the new volume, we need to assume that the temperature is constant.
To solve this problem, we need to use Boyle's Law. Boyle's Law establishes when the temperature is kept constant, the pressure and the volume will be proportional.
Boyle's Law equation is:

So, we are given the information:

Then, isolating the new volume and substituting into the equation, we have:



Hence, the new volume will be 1 L.

Have a nice day!
Answer:
b
Explanation:
[H3O+] = 10-pH = 10-3.4 ≅ 3.981 x 10^-4 moles/liter