Answer:
the period of this graph is 2
Step-by-step explanation:
The period is the length of the section that repeats. So for this graph, we need to calculate the distance between 2 peaks or 2 troughs of the curve.
Let's look at the peaks (maximums).
One is at x = 0 and the next is at x = 2
2
- 0 = 2
Therefore, the period of this graph is 2
Answer:
18
Step-by-step explanation:
q^2 - 5q +4
Let q = -2
(-2)^2 - 5(-2) +4
4 + 10 +4
18
Sometimes
1. The radical expression
![\sqrt[n]{}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7B%7D%20)
with even n requires <span>a variable with positive quantity. For example, if you have
![\sqrt[4]{x^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7Bx%5E3%7D%20)
, then always

.
</span>
2. If you have radical expression
![\sqrt[n]{}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7B%7D%20)
with odd n, ia variable may be arbitrary. For example, for
![\sqrt[7]{x}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7Bx%7D%20)
you can consider all real x.
To find the solutions to the system, we need to find exactly when one expression is equal to the other. We can do this by setting both of the right sides equal to each other, so that

Subtracting x+6 from either side, we find

factoring out an x+6:


The x-coordinates of our solutions will therefore be 6 and -6. Since the question only asks for the <em>x-coordinate</em> of the midpoint, we simply need to find the number exactly halfway between 6 and -6, which is 0.
Hey there, just subtract 4 1/3 from 3 2/3 to get your answer. 4 1/3=13/3 and 3 2/3=11/3, 13*3-11*3/3*3=39-33/9=6/9, 6/9 simplified is 2/3