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Masteriza [31]
3 years ago
6

The expression 1/4y+3/8 factored is

Mathematics
1 answer:
olganol [36]3 years ago
5 0

Answer:

1/8(2y + 3).

Step-by-step explanation:

The greatest common factor of 1/4 and 3/8 is 1/8.

So we divide each term by 1/8:

1/4y+3/8  = 1/8(2y + 3).

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You have a pizza with diameter 14 2/3 in and a square box that is 14.68 in. across. Write 14 2 /3 decimal. Can you fit the pizza
Elena L [17]

Answer:

Well 14 2/3 is 14.66 so it would be B but yea it would fit.

6 0
3 years ago
Determine whether the following sequence is geometric. 2,6,18,54
jonny [76]

Answer: Yes, this is a geometric sequence.

Step-by-step explanation:

This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by  3  gives the next term.

8 0
3 years ago
I need help with 20.
irinina [24]

Step-by-step explanation:

why ? you did it right there already.

the numerator is the top part of the fraction, the "counting" part (how many units of a certain type or size are there).

the denominator (the bottom part) is defining the type or size of units described by the fraction.

so, we are adding 4 to the numerator of 2/5, making it (2+4)/5 = 6/5

what do we need to add to the denominator (the bottom part) to make the fraction have the value of 1/2 ?

so, what x would make 6/x = 1/2 ?

6 = x/2

x = 6×2 = 12

so, we need to get 12 in the denominator, where we have currently 5.

therefore, we need to add 12-5 = 7 to it.

so that

6/(5+7) = 6/12 = 1/2

3 0
2 years ago
Place a point where you think
just olya [345]
Root 78 would go Between 8 and 9
5 0
2 years ago
Suppose that a recent poll of American households about car ownership found that for households with a car, 39% owned a sedan, 3
Dimas [21]

Let the total number of cars = 100

Total of sedan, van and sports cars = 39+33+7 = 79

Number of other cars = 100 - 79 = 21.

Let A be the event of owning a sedan,

B be the event of owning a van and

C be the event of owning a sports car.

D be the event of owning other cars.

Then, p(A) = \frac{39}{100}

p(B)=\frac{33}{100} and

p(C) = \frac{7}{100}

p(D) = \frac{21}{100}

Now,

p(non selection of van) = p(A ∪ C ∪ D)

= p(A) + p(C) + p(D)

=\frac{39}{100} +\frac{7}{100} +\frac{21}{100}

=\frac{67}{100}

= 0.67

The probability of none of the three selections would be a van is:

0.67 × 0.67 × 0.67

= 0.300763

=0.301

Hence, the correct option is (D).

6 0
3 years ago
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