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Nimfa-mama [501]
2 years ago
7

If PQ and RS intersect from four right angles which statement is true

Mathematics
1 answer:
Harman [31]2 years ago
8 0

Answer:

Right angles = 90 if more its not a right angle


Step-by-step explanation:


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\bf \cfrac{4a}{3}-\cfrac{b}{4}=6&#10;\qquad \qquad &#10;\cfrac{5a}{6}+b=13&#10;\\\\\\&#10;\textit{let us remove the denominators off those folks}\\&#10;\textit{by multiplying the first one by 12, both sides}\\&#10;\textit{and the second one by 6, both sides, thus}&#10;\\\\\\&#10;12\left( \cfrac{4a}{3}-\cfrac{b}{4} \right)=12(6)\implies 16a-4b=72&#10;\\\\\\&#10;6\left( \cfrac{5a}{6}+b \right)=6(13)\implies 5a+6b=78

\bf  \textit{now, let's do the elimination}&#10;\\\\&#10;&#10;\begin{array}{llll}&#10;16a-4b=72&\boxed{\times 3}\implies &48a-\underline{12b}=216\\\\&#10;5a+6b=78&\boxed{\times 2}\implies &10a+\underline{12b}=156\\&#10;&&--------\\&#10;&&58a+0\quad=372&#10;\end{array}

solve for "a", once you get "a", plug it back into either equation to get "b"
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