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victus00 [196]
3 years ago
5

Atasha is solving the equation x^2-x=-3 with the quadratic formula.

Mathematics
1 answer:
AlekseyPX3 years ago
7 0

Answer:

a= 1

b= -1

c= 3

Step-by-step explanation:

''a'' and "b" are the coefficients of x^2 and x respectively, where "c" is the constant number.

When solving a quadratic equation all the variables and constants should be on one side, in this case: x^2 -x +3=0.

Here the coefficient of x^2 is one, of x is -1 and constant is 3.

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Tony is at a car rental service to rent a car. There is an administration fee of $50 to rent a car and then it costs $20 for eac
Nookie1986 [14]

Answer:

20x+50

Step-by-step explanation:

Let x represent the number of days he has the car

20x+50

It is 20x, because it costs 20 dollars for each day he has the car, and +50, because there is a fee, regardless of how many days he has the car.

Hope this helps!

7 0
3 years ago
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galina1969 [7]
I hope this helps you

8 0
3 years ago
An organic farm has been growing an heirloom variety of summer squash. A sample of the weights of 40 summer squash revealed that
natta225 [31]

Answer:

b. 0.0228

Step-by-step explanation:

We are given that

n=40

Mean,\mu=402.7 g

Standard deviation, \sigma=8.8g

We have to find the probability hat the mean weight for a sample of 40 summer squash exceeds 405.5 grams.

P(x>405.5)=P(\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}>\frac{405.5-402.7}{\frac{8.8}{\sqrt{40}}})

P(x>405.5)=P(Z>\frac{2.8}{\frac{8.8}{\sqrt{40}}})

P(x>405.5)=P(Z>2.01)

P(x>405.5)=1-P(Z\leq 2.01)

P(x>405.5)=1-0.977784

P(x>405.5)=0.022216

Hence, option b is correct.

5 0
3 years ago
What is the value of x.
Neporo4naja [7]

Answer:

Without any question we cant signify it !!!!!!????

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find a numerical value of one trigonometric function of x for cscx = sinx tanx + cosx
Alex787 [66]

Answer:

Step-by-step explanation:

we have

cscx = sinx tanx + cosx\\\\\frac{1}{sinx}=sinx.\frac{sinx}{cosx} +cosx\\\\\frac{1}{sinx}.sinx.cosx= sinx.\frac{sinx}{cosx}.sinx.cosx+cosx.sinx.cosx\\  cosx= (sinx)^{3} +sinx.(cosx)^{2} \\cosx= sinx[(sinx)^{2}+(cosx)^{2})\\  cosx=sinx.1\\cosx=sinx\\tanx=1\\x=\frac{\pi}{4} +k\pi,k-integer.

6 0
3 years ago
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