Answer:
1/2, 1/4 & 3/4
Step-by-step explanation:
mean of 0 &1 is
mean of 0 and 1/2 is 
mean of 1/2 and 1 is 
So the three rational numbers are 1/2, 1/4 & 3/4
-7/6, -5/4, -2.8, 1.3, 4/3
7g - 6 = -20
Add 6 to both sides
7g = -14
Divide both sides by 7
g = -2
answer: g = -2
<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>