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3 years ago

6. Emma uses 10 pages of paper when she writes anything. She uses an

Mathematics

1 answer:

Savatey [412]3 years ago

6 0

Answer:

4x+10

Step-by-step explanation:

Emma is guaranteed to use 10 pages when she writes something. Since you can't tell how many hours she has written, you use x to represent the hours she has spent writing. If she writes 4 pages every hour, that would be 4 × (hours spent writing) or 4x. Add 4x to the original guaranteed 10 pages she uses and you have your expression.

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Find the mean of:<br> 16 32 10 28 8 19 32 26<br> 33 39 98 399

iren2701 [21]

Answer:

91.125

Step-by-step explanation:

Total number/ Total number of quantity

16+32+10+28+8+19+32+26+33+39+98+399

729

Divode by number of quantity (8)

729/8

=91.125

Hope this helps, dont hesitate to Ask in comment below. Mark me as brainliest also appriciated!!

5 0

3 years ago

What is 16,473 to the nearest hundred

Verizon [17]

The number "4" is in the hundreds place. To the right is 7, and since it's greater than five it rounds up. So 16,473 to the nearest hundred is 16,500. Hope this helped!

4 0

3 years ago

What is the formula for intersecting chords on the interior of a circle?

Ratling [72]

Answer:

Each chord is cut into two segments at the point of where they intersect. One chord is cut into two line segments A and B. The other into the segments C and D. This theorem states that A×B is always equal to C×D no matter where the chords are.

4 0

3 years ago

Write an equation to find the amount of interest $450,000 earns in 1 year at a simple interest rate of 3.5%.

telo118 [61]

Answer:

The required equation for the amount of Simple Internet = $\frac{450,000 \times 1 \times 3.5}{100}$

Step-by-step explanation:

Here , Principal amount = $450,000

Time = 1 year

Rate of Interest = 3.5%

Now,SIMPLE INTEREST = $\frac{P \times R \times T}{100}$

So, here SI = $\frac{450,000 \times 1 \times 3.5}{100}$

Hence, the required equation for the amount of Simple Internet = $\frac{450,000 \times 1 \times 3.5}{100}$

7 0

4 years ago

Read 2 more answers

A researcher is going to estimate the average typing speed of students of a college. He selects a random sample of 20 students a

Stella [2.4K]

Answer:

The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.9}{2} = 0.95$ . So we have T = 1.7291

The margin of error is:

$M = T\frac{s}{\sqrt{n}}$

In which s is the standard deviation of the sample and n is the size of the sample. For this question, we have $s = 5, n = 20$ . So

$M = T\frac{s}{\sqrt{n}}$

$M = 1.7291\frac{5}{\sqrt{20}}$

$M = 1.933$

The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.

8 0

3 years ago