Answer:
x = 4√5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Trigonometry</u>
[Right Triangles Only] Pythagorean Theorem: a² + b² = c²
- a is a leg
- b is another leg
- c is the hypotenuse<u>
</u>
Step-by-step explanation:
<u>Step 1: Define</u>
Leg <em>a</em> = 8
Leg <em>b</em> = 4
Hypotenuse <em>c</em> = <em>x</em>
<em />
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute in variables [Pythagorean Theorem]: 8² + 4² = x²
- Evaluate exponents: 64 + 16 = x²
- Add: 80 = x²
- [Equality Property] Square root both sides: √80 = x
- Rewrite: x = √80
- Simplify: x = 4√5
9 is the answer for that problem
The answer is in the picture! I hope this helps!
To add and get the sum
346
421
+152
We start on the ones place 6 + 1 + 2 = 9, the sum of the digits in the ones place is not up to 10, we will not regroup this ones place.
So, basically the answer to 13a is NO.
Since we are not able to regroup the ones place there is no regrouped tens to add, therefore the answer to 13b is also NO.
Next is the tens place, 4 +2 +5 = 11, the sum of the digits in the ones place is up to 10 so we regroup the tens place.
Thus, the answer to 13c is YES.
Since, we regrouped the ones place, we add the regrouped hundred, thus the answer to 13d is YES.
Finally, for the hundred place, 1 + 3 + 4 + 1 = 9
Therefore, the sum of
346
421
+ 152
is 919
