1) 4*3 - 9
2) 15 - 12
3) 4 - 1
4) 54 + 1 - 52
5) 9*3+2-26
Hope this helps!
R=1v+h([pi]h^2) all over 3
Answer:
perimeter of triangle IJH= 17.5
Step-by-step explanation:
line IJ is a midsegment, so you can divide the segments FH and GH by 2.
that means segment IH= 4.5 and segment GH=6. segment IJ is given as 7.
add 4.5 + 6 + 7, which equals 17.5
