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vovangra [49]
3 years ago
14

What is the solution to 4x -10 > X - 12? (-0, -18) (-18.00) 06-0, 18) (18,6)

Mathematics
2 answers:
const2013 [10]3 years ago
7 0

Answer:

-18, infinity

Step-by-step explanation:

I did on edgenuity and got it correct

mixas84 [53]3 years ago
4 0

Answer:

\large\boxed{x>-\dfrac{2}{3}\to x\in\left(-\dfrac{2}{3},\ \infty\right)}

Step-by-step explanation:

4x-10>x-12\qquad\text{add 10 to both sides}\\4x-10+10>x-12+10\\4x>x-2\qquad\text{subtract}\ x\ \text{from both sides}\\4x-x>x-x-2\\3x>-2\qquad\text{divide both sides by 3}\\\dfrac{3x}{3}>\dfrac{-2}{3}\\x>-\dfrac{2}{3}

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The expression c + 0.07c can be used to find the total cost of an item with 7% sales tax, where c is the cost of the item. Use t
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<h3>Total Cost </h3>

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Axis of sym: x =
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Answer:

<h2>SEE BELOW</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • quadratic function
  • PEMDAS
<h3>let's solve:</h3>

vertex:(h,k)

therefore

vertex:(-1,4)

axis of symmetry:x=h

therefore

axis of symmetry:x=-1

  • to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0

vertex form of quadratic equation:

  • y=a(x-h)²+k

therefore

  • y=a(x-(-1))²+4
  • y=a(x+1)²+4

it's to notice that we don't know what a is

therefore we have to figure it out

the graph crosses y-asix at (0,3) coordinates

so,

3=a(0+1)²+4

simplify parentheses:

3 = a(1 {)}^{2}  + 4

simplify exponent:

3 =  a + 4

therefore

a =  - 1

our vertex form of quadratic equation is

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let's simplify it to standard form

simplify square:

y =  - ( {x}^{2}  + 2x + 1)  + 4

simplify parentheses:

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simplify addition:

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therefore our answer is D)y=-x²-2x+3

the domain of the function

x\in \mathbb{R}

and the range of the function is

y\leqslant 4

zeroes of the function:

-  {x}^{2}  - 2x + 3 = 0

\sf divide \: both \: sides \: by \:  - 1

{x}^{2}  + 2x - 3 = 0

\implies \:  {x}^{2} +   3x  - x  +  3 = 0

factor out x and -1 respectively:

\sf \implies \: x(x + 3)   - 1(x  + 3 )= 0

group:

\implies \: (x - 1)(x + 3) = 0

therefore

\begin{cases} x_{1} = 1 \\  x_{2}  =  - 3\end{cases}

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