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Romashka [77]
4 years ago
10

Simplify the radical expression. PLEASE HELP!!!

Mathematics
2 answers:
IgorC [24]4 years ago
8 0
<span>√15y * 3√81y
=27y</span>√15

answer is <span>d) 27y√15</span>
andrew-mc [135]4 years ago
4 0
√15y*3√81y

√15y*√729y

√10935y^2

√729*15*y2

27y√15

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The hardcover version of a book weighs twice as much as its paperback version. The hardcover book and the paperback together wei
jasenka [17]

I think  H=P*2/4.2 could work corrext me if im wrong please


5 0
3 years ago
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What is tan 30°?<br><br>30°<br>​
schepotkina [342]

Answer:

i think its =0.5773502692

7 0
4 years ago
Line CD bisects AB at point C. Find AC if AB = 56 feet
RideAnS [48]

Answer:

  AC = 28 feet

Step-by-step explanation:

Point C is the midpoint of AB, so AC is half the length of AB:

  AB/2 = (56 ft)/2 = 28 ft = AC

8 0
4 years ago
In △ABC, point P∈ AC with AP:PC=1:3, point Q∈AB so that AQ:QB=3:4, Find the ratios APBQ : APBC and AAQP : AABC.
weqwewe [10]

Answer: The  ratios APBQ : APBC=4:21 and AAQP : AABC= 3:28

Explanation:

Here, ABC is a triangle where, P and Q are the midpoints of the edges AC and AB respectively,

Now, according to the question ,AP:PC=1:3 let AP=x and PC=3x where x is any real number. Thus, AC=AP+AC= x+3x= 4x

Similarly,  AQ:QB=3:4 let AQ=3y and QB=4y where y is also any real number. Thus, AB=AQ+QB=3y+4y=7y

Since, \frac{AP.BQ}{AP.BC} =\frac{AP.BQ}{AB.PC} =\frac{x.4y}{7y.3x} =\frac{4xy}{21xy} =\frac{4}{21}

And, \frac{AA.QP}{AA.BC} =\frac{AQ.AP}{AB.AC} =\frac{3y.1x}{7y.4x} =\frac{3xy}{28xy} =\frac{3}{28}

5 0
4 years ago
2x-5y=3 4y-x=-3 solve by elimination
loris [4]

Answer:

x = -1 and y = -1

Step-by-step explanation:

to solve this equation we say

let

2x-5y=3.......................................... equation 1

4y-x=-3............................................equation 2

from equation 2

4y-x=-3............................................equation 2

4y + 3 = x

i.e

x = 4y + 3 .............................................  equation 3

put x = 4y + 3 in equation 1

2(4y +3) - 5y = 3

8y + 6 -5y = 3

3y +6 = 3

3y= 3-6

3y -3

divide both sides by the coefficient  of y  which is 3

3y/3 = -3/3

y = -1

put y = -1 into equation 3

x = 4y + 3 .............................................  equation 3

x = 4(-1) + 3

x = -4 + 3

x = -1

therefore the value of x = -1 and y = -1 respectively

4 0
3 years ago
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