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lbvjy [14]
3 years ago
9

A triangle with vertices (−3, −3), (−6, 2), and (−1, 5) is what type of triangle? A) Equilateral B) Scalene C) Right D) Isoscele

s right
Mathematics
1 answer:
aalyn [17]3 years ago
3 0
<span>C) Right

https://www.desmos.com/calculator/vf2qksnpwe

</span>right triangle
<span>Proof: You can apply the Pythagorean theorem.</span>
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A student has some​ $1 and​ $5 bills in his wallet. He has a total of 14 bills that are worth ​$34. How many of each type of bil
jeka57 [31]

Solution:

we are given that

A student has some​ $1 and​ $5 bills in his wallet.

Let there x $1 bills and y number of $5 bills.

He has a total of 14 bills that are worth ​$34.

So we can write

x+y=14

x+5y=34

Now solve these two equations together using substitution as follows

14-y+5y=34\\&#10;\\&#10;4y=34-14\\&#10;\\&#10;4y=20\\&#10;\\&#10;y=5\\&#10;\\&#10;x=14-y=14-5=9\\

Hence there are 9 $1 bills and 5 bills are of $5.

5 0
3 years ago
HELP ME PLSSSSS IM BEGGING UUUU!!!!!
Mrac [35]

Answer:

D

Step-by-step explanation:

6 0
3 years ago
Sweets are sold loose, or pre-packed in 120g bags. The 120g bags are ?1.49 each. The loose sweets are ?0.89 for 100g. By calcula
tester [92]

Answer:

The loose sweets at ?0.89 for 100 g.


Step-by-step explanation:

First, calculate the price per gram. You do this by dividing the price by the grams.

?1.49 / 120 g =  1.49 / 120 = 0.0124 (4 dp)

Because the answer was very long, I have rounded it to 4 decimal places (4 dp).

?0.89 / 100 g = 0.89 / 100 = 0.0089

Next, you must calculate both pre-packed and loose sweets to the same weight. I am calculating them both to 100 g.

0.0124 x 100 = 1.24

0.0089 x 100 = 0.89

Finally, the cheapest product for 100 g will be the better value. In this case, it is the loose sweets.






6 0
3 years ago
Please help me find out the process to find y for the first three questions and tell me what y is
Sliva [168]

Answer:

1. y = 14.718

2. ??

3. y = 39.794°

Step-by-step explanation:

<em>HINT the side we already know and the side we are trying to find, we use the first letters of their names and the phrase "SOHCAHTOA" to decide which function: </em>

SOH...

 Sine: sin(θ) = Opposite / Hypotenuse

...CAH...

 Cosine: cos(θ) = Adjacent / Hypotenuse

...TOA

 Tangent: tan(θ) = Opposite / Adjacent

1. Sine: sin(θ) = Opposite / Hypotenuse

sin(42°) = y / 22

so on your calculator enter 42 then sin = 0.669

0.669 = y/22      multiply both sides by 22 to get y

y = 14.718

2. is there any other information??

3. The two sides we know are Opposite 40 and Adjacent 48.

SOHCAHTOA tells us we must use Tangent.

Calculate Opposite/Adjacent = 40/48 = 0.833

Find the angle from your calculator using tan-1

Tan y° = opposite/adjacent = 40/48 = 0.833  

tan-1 of 0.833 = 39.794°

7 0
3 years ago
Find the discriminant and determine the nature of the roots to the quadratic equation
Katen [24]
№17
x^{2} +6x-7=0 \\ D=6 ^{2} -4*(-7)=36+28=64=8 ^{2}  \\  \\  x_{1} = \frac{-6+8}{2} =1 \\  \\  x_{2} = \frac{-6-8}{2} =-7
Answer: x₁ = 1
               x₂ = - 7

№18
2 x^{2} -3x+4=3 \\ 2 x^{2} -3x+4-3=0 \\ 2 x^{2} -3x+1=0 \\  \\ D= -3 ^{2} -4*2=9-8=1 \\  \\  x_{1} = \frac{3+1}{2*2} = \frac{4}{4} =1 \\  \\  x_{2} = \frac{3-1}{2*2} = \frac{2}{4} =0.5
Answer: x₁ = 1
               x₂ = 0,5.

№19
2 x^{2} -4x-5=0 \\  D=-4 ^{2} -4*2*(-5)=16+40=56 \\  \\  x_{1}= \frac{4+ \sqrt{56} }{2*2}  = \frac{4}{4} + \sqrt{ \frac{56}{16} } =1+ \sqrt{3.5}  \\  \\  x_{2} = \frac{4- \sqrt{56} }{2*2} = \frac{4}{4} -  \sqrt{ \frac{56}{16} } =1- \sqrt{3.5} &#10;
Answer: x₁ = 1 + √3.5
               x₂ = 1 - √3.5

3 0
3 years ago
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